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Which of the following would form a buffer if added to \(295 \mathrm{~mL}\) of \(0.380 \mathrm{M} \mathrm{HCl}\) ? (a) \(0.100 \mathrm{~mol}\) of \(\mathrm{NH}_{4} \mathrm{Cl}\) (b) \(0.033 \mathrm{~mol}\) of \(\mathrm{KF}\) (c) \(0.167 \mathrm{~mol}\) of \(\mathrm{Sr}(\mathrm{OH})_{2}\) (d) \(0.279 \mathrm{~mol}\) of \(\mathrm{KNO}_{2}\) (e) \(0.112 \mathrm{~mol}\) of \(\mathrm{KClO}\)

Short Answer

Expert verified
Answer: 0.279 mol of KNO2

Step by step solution

01

Determine the concentrations of HCl before adding any substances

: Before adding anything, we have a 0.380 M HCl solution. So to start, calculate the moles of HCl in the initial solution: Moles of HCl = (Volume)(Concentration) = (295 mL)(0.380 mol/L) = 0.295 L × 0.380 mol/L = 0.112 mol
02

Analyze each substance and whether it would create a buffer solution

: (a) 0.100 mol of NH4Cl: Here, we have NH4Cl, which is a salt of a weak base (NH4+) and a strong acid (Cl-). When NH4Cl is added, the weak base NH4+ will react with the strong acid HCl. Since there is excess HCl, there will be no conjugate pair formed. Hence it won't form a buffer solution. (b) 0.033 mol of KF: KF is a salt of a weak acid (HF) and a strong base (K+). Since the weak acid is not present to react with HCl, it won't form a buffer. (c) 0.167 mol of Sr(OH)2: Sr(OH)2 is a strong base, and it reacts completely with the acid HCl. There won't be any weak base left after the reaction, so it won't form a buffer solution. (d) 0.279 mol of KNO2: KNO2 is a salt of weak acid (HNO2) and strong base (K+). It dissociates into K+ and NO2- ions. The NO2- ion, a conjugate base, reacts with HCl to produce weak acid HNO2. Since the amount of NO2- (0.279 mol) is more than HCl (0.112 mol), we'll still have NO2- ions after the reaction. Hence, we have a weak acid (HNO2) and its conjugate base (NO2-) existing simultaneously, and it forms a buffer solution. (e) 0.112 mol of KClO: KClO is a salt of a strong acid (K+) and a weak base (ClO-). Due to the absence of a suitable conjugate acid pair, it cannot react with HCl to form a buffer solution.
03

Choose the correct option

: Based on the analysis, the correct option is (d) 0.279 mol of KNO2 as it forms a buffer solution with HCl by providing a weak acid (HNO2) and its conjugate base (NO2-) simultaneously in the resulting solution.

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Most popular questions from this chapter

A solution with a pH of 9.22 is prepared by adding water to \(0.413 \mathrm{~mol}\) of KX to make \(2.00 \mathrm{~L}\) of solution. What is the \(\mathrm{pH}\) of the solution after \(0.368 \mathrm{~mol}\) of \(\mathrm{HX}\) is added?

A buffer is prepared by dissolving \(0.062 \mathrm{~mol}\) of sodium fluoride in \(127 \mathrm{~mL}\) of \(0.0399 \mathrm{M}\) hydrofluoric acid. Assume no volume change after \(\mathrm{NaF}\) is added. Calculate the \(\mathrm{pH}\) of this buffer.

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A \(20.00-\mathrm{mL}\) sample of \(0.220 \mathrm{M}\) triethylamine, \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{~N}\), is titrated with \(0.544 \mathrm{M} \mathrm{HCl} .\left(\mathrm{K}_{\mathrm{b}}\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{~N}=5.2 \times 10^{-4}\right)\) (a) Write a balanced net ionic equation for the titration. (b) How many milliliters of \(\mathrm{HCl}\) are required to reach the equivalence point? (c) Calculate \(\left[\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{~N}\right],\left[\left(\mathrm{CH}_{3} \mathrm{CH}_{2}\right)_{3} \mathrm{NH}^{+}\right],\left[\mathrm{H}^{+}\right],\) and \(\left[\mathrm{Cl}^{-}\right]\) at the equivalence point. (Assume that volumes are additive.) (d) What is the \(\mathrm{pH}\) at the equivalence point?

A \(35.00-\mathrm{mL}\) sample of \(0.487 \mathrm{M} \mathrm{KBrO}\) is titrated with \(0.264 \mathrm{M} \mathrm{HNO}_{3} \cdot\left(K_{\mathrm{b}} \mathrm{BrO}^{-}=4.0 \times 10^{-6}\right)\) (a) Write a balanced net ionic equation for the reaction. (b) How many milliliters of \(\mathrm{HCl}\) are required to reach the equivalence point? (c) What is the \(\mathrm{pH}\) at the equivalence point? (d) Calculate \(\left[\mathrm{K}^{+}\right],\left[\mathrm{NO}_{3}^{-}\right],\left[\mathrm{H}^{+}\right],\left[\mathrm{BrO}^{-}\right],\) and \([\mathrm{HBrO}]\) at the equivalence point. (Assume volumes are additive.)

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