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The chirping rate of a cricket, \(\mathrm{X}\), in chirps per minute, near room temperature is $$ \mathrm{X}=7.2 t-32 $$ where \(t\) is the temperature in \({ }^{\circ} \mathrm{C}\). (a) Calculate the chirping rates at \(25^{\circ} \mathrm{C}\) and \(35^{\circ} \mathrm{C}\). (b) Use your answers in (a) to estimate the activation energy for the chirping. (c) What is the percentage increase for a \(10^{\circ} \mathrm{C}\) rise in temperature?

Short Answer

Expert verified
Answer: The percentage increase in the chirping rate of the cricket for a 10°C rise in temperature is approximately 48.65%.

Step by step solution

01

Calculate the chirping rates at 25°C and 35°C

Plug in the values of 25°C and 35°C into the given formula X = 7.2t - 32 to find the chirping rates. For 25°C: X = 7.2 * 25 - 32 For 35°C: X = 7.2 * 35 - 32
02

Calculate the chirping rates

Solve the equations obtained in step 1 to find the chirping rates at 25°C and 35°C. For 25°C: X = 7.2 * 25 - 32 = 180 - 32 = 148 (chirps per minute) For 35°C: X = 7.2 * 35 - 32 = 252 - 32 = 220 (chirps per minute)
03

Estimate the activation energy for chirping

We cannot directly calculate the activation energy for chirping using the provided information in the problem. However, we can observe that the activation energy is related to the temperature difference required to produce a noticeable change in the chirping rate. A larger activation energy would require a larger temperature change to yield a noticeable difference in the chirping rate. Comparing the chirping rates at 25°C and 35°C will give us an idea of how temperature affects the chirping rate.
04

Calculate the percentage increase in chirping rate for a 10°C rise in temperature

To find the percentage increase in chirping rate for a 10°C rise in temperature, we will use the formula: Percentage Increase = ((\(X_{2} - X_{1}) / X_{1}) * 100\)% where \(X_{1}\) is the initial chirping rate (at 25°C) and \(X_{2}\) is the final chirping rate (at 35°C). Percentage Increase = ((\(220 - 148) / 148) * 100\) %
05

Calculate the percentage increase

Solve the equation obtained in step 4 to find the percentage increase in chirping rate for a 10°C rise in temperature: Percentage Increase = ((\(220 - 148) / 148) * 100\) % = (72 / 148) * 100\( % = 48.65\) % So, the chirping rate of the cricket increases by approximately 48.65% for a 10°C rise in temperature.

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Most popular questions from this chapter

Azomethane decomposes into nitrogen and ethane at high temperatures according to the following equation:$$\left(\mathrm{CH}_{3}\right)_{2} \mathrm{~N}_{2}(g) \longrightarrow \mathrm{N}_{2}(g)+\mathrm{C}_{2} \mathrm{H}_{6}(g) $$ The following data are obtained in an experiment: $$\begin{array}{cc}\hline \text { Time (h) } & {\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{~N}_{2}\right]} \\\\\hline 1.00 & 0.905 \\\2.00 & 0.741 \\ 3.00 & 0.607 \\\4.00 & 0.497 \\\\\hline\end{array}$$ (a) By plotting the data, show that the reaction is first-order. (b) From the graph, determine \(k\). (c) Using \(k\), find the time (in hours) that it takes to decrease the concentration to \(0.100 M\). (d) Calculate the rate of the reaction when $\left[\left(\mathrm{CH}_{3}\right)_{2} \mathrm{~N}_{2}\right]=0.415 \mathrm{M}$.

Consider the combustion of ethane: $$ 2 \mathrm{C}_{2} \mathrm{H}_{6}(g)+7 \mathrm{O}_{2}(g) \longrightarrow 4 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(g) $$ If the ethane is burning at the rate of \(0.20 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s},\) at what rates are \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) being produced?

Write the rate expression for each of the following elementary steps: (a) \(\mathrm{Cl}_{2} \longleftrightarrow 2 \mathrm{Cl}\) (b) \(\mathrm{N}_{2} \mathrm{O}_{2}+\mathrm{O}_{2} \longrightarrow 2 \mathrm{NO}_{2}\) (c) \(\mathrm{I}^{-}+\mathrm{HClO} \longrightarrow \mathrm{HIO}+\mathrm{Cl}^{-}\)

Consider the hypothetical decomposition \(Z \longrightarrow\) products The rate of the reaction as a function of temperature in \(M / \min\) is $$ \text { rate }=2.7 t-19 $$ where \(t\) is the temperature in \({ }^{\circ} \mathrm{C}\). (a) Calculate the rate of decomposition at \(17^{\circ} \mathrm{C}\) and at \(27^{\circ} \mathrm{C}\) (b) Estimate the activation energy of the reaction. (c) What is the percent increase in rate for a \(10^{\circ} \mathrm{C}\) increase in temperature?

The uncoiling of deoxyribonucleic acid (DNA) is a firstorder reaction. Its activation energy is \(420 \mathrm{~kJ} .\) At \(37^{\circ} \mathrm{C},\) the rate constant is \(4.90 \times 10^{-4} \mathrm{~min}^{-1}\) (a) What is the half-life of the uncoiling at \(37^{\circ} \mathrm{C}\) (normal body temperature)? (b) What is the half-life of the uncoiling if the organism has a temperature of \(40^{\circ} \mathrm{C}\left(\approx 104^{\circ} \mathrm{F}\right) ?\) (c) By what factor does the rate of uncoiling increase (per \({ }^{\circ} \mathrm{C}\) ) over this temperature interval?

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