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Titanium is a metal used in jet engines. Its specific heat is \(0.523 \mathrm{~J} / \mathrm{g} \cdot{ }^{\circ} \mathrm{C}\). If \(5.88 \mathrm{~g}\) of titanium absorbs \(4.78 \mathrm{~J}\), what is the change in temperature?

Short Answer

Expert verified
Answer: The change in temperature of the titanium is approximately 1.47°C.

Step by step solution

01

Write the given values.

We are given: Specific heat of titanium (c) = 0.523 J/g °C Mass of titanium (m) = 5.88 g Energy absorbed (q) = 4.78 J
02

Write the formula for calculating the change in temperature (ΔT).

The formula for calculating the change in temperature is: \(q = mcΔT\)
03

Rearrange the formula for ΔT.

We need to find ΔT, so we will rearrange the formula: \(ΔT = \frac{q}{mc}\)
04

Plug in the given values and calculate ΔT.

Now we will substitute the given values for q, m, and c in the formula: \(ΔT = \frac{4.78 \mathrm{~J}}{5.88 \mathrm{~g} \times 0.523 \mathrm{~J / g\cdot ^{\circ}C}}\)
05

Solve for ΔT.

Now, calculate the value of ΔT: \(ΔT = \frac{4.78 \mathrm{~J}}{ (5.88 \mathrm{~g}) \times (0.523 \mathrm{~J / g\cdot ^{\circ}C})} \approx 1.47^{\circ} C\) The change in temperature of the titanium is approximately 1.47°C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Energy
Thermal energy refers to the total energy present within a substance due to the random motion of its molecules. It is important to distinguish between thermal energy and temperature, as they are not the same. While temperature measures the average kinetic energy of particles in a substance, thermal energy accounts for both the temperature and the number of particles, or the mass, in the substance.
In our exercise, thermal energy is involved when the titanium absorbs the heat, which then causes a change in its temperature. This energy is measured in joules (J), which is a standard unit of energy in physics and other sciences. When titanium absorbs 4.78 J of energy in this problem, we are witnessing the process of thermal energy being transferred to the metal thereby falling under the principle of thermal dynamics.
Understanding thermal energy allows us to comprehend how energy interchange takes place in various materials, and why the heat capacity of substances, like titanium in this case, is crucial for determining how much temperature change occurs when heat is absorbed.
Temperature Change
Temperature change (\(\Delta T\)) is the measure of how much the temperature of an object increases or decreases after absorbing or releasing heat. In this exercise, we aim to calculate the temperature change of titanium upon the absorption of a certain amount of energy.
To calculate the temperature change, we use the formula:\[\Delta T = \frac{q}{mc}\]This equation states that the change in temperature depends on the amount of energy transferred (\(q\)), the mass of the substance (\(m\)), and the specific heat capacity of the substance (\(c\)).
In the given task, the titanium absorbs 4.78 J of energy, and we need to find how much this affects the temperature. The available data: mass (5.88 g) and specific heat (0.523 J/g°C), need to be substituted into the formula to solve for the temperature change. Following this calculation, it becomes evident that the 4.78 J increases the temperature by approximately 1.47°C.
Heat Capacity
Heat capacity is the total amount of heat energy required to change the temperature of an object by a given amount, typically one degree Celsius. It is intimately related to the specific heat, which describes the heat capacity per unit mass of a substance. The specific heat capacity provides insight into how resistant a material is to changing temperature.
For titanium, its specific heat capacity is given as 0.523 J/g°C in the exercise. This tells us that it takes 0.523 J of energy to raise 1 gram of titanium by 1°C. This specific heat capacity value, along with the mass of the titanium, plays a crucial role in our calculations because it influences how much energy is needed to achieve a certain temperature change.
  • Higher specific heat means the material will require more energy to increase its temperature.
  • Lower specific heat means it will heat up with less energy input.
In practical terms, understanding heat capacity helps in designing systems that manage heat exchange efficiently, like those found in engines and other mechanical applications where metals like titanium are used.

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Most popular questions from this chapter

Strontium metal is responsible for the red color in fireworks. Fireworks manufacturers use strontium carbonate, which can be produced by combining strontium metal, graphite (C), and oxygen gas. The formation of one mole of \(\mathrm{SrCO}_{3}\) releases \(1.220 \times 10^{3} \mathrm{~kJ}\) of energy. (a) Write a balanced thermochemical equation for the reaction. (b) What is \(\Delta H\) when \(10.00 \mathrm{~L}\) of oxygen at \(25^{\circ} \mathrm{C}\) and \(1.00 \mathrm{~atm}\) is used by the reaction?

Write thermochemical equations for the formation of one mole of the following compounds from the elements in their stable states at \(25^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\). (a) acetylene, \(\mathrm{C}_{2} \mathrm{H}_{2}(g)\) (b) nitrogen dioxide \((g)\) (c) lead(II) bromide (s) (d) phosphorus pentachloride \((g)\)

To produce silicon, used in semiconductors, from sand \(\left(\mathrm{SiO}_{2}\right)\), a reaction is used that can be broken down into three steps: $$ \begin{aligned} \mathrm{SiO}_{2}(s)+2 \mathrm{C}(s) \longrightarrow \mathrm{Si}(s)+2 \mathrm{CO}(g) & & \Delta H=689.9 \mathrm{~kJ} \\ \mathrm{Si}(s)+2 \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{SiCl}_{4}(g) & & \Delta H=-657.0 \mathrm{~kJ} \\ \mathrm{SiCl}_{4}(g)+2 \mathrm{Mg}(s) \longrightarrow 2 \mathrm{MgCl}_{2}(s)+\mathrm{Si}(s) & & \Delta H=-625.6 \mathrm{~kJ} \end{aligned} $$ (a) Write the thermochemical equation for the overall reaction for the formation of silicon from silicon dioxide; \(\mathrm{CO}\) and \(\mathrm{MgCl}_{2}\) are byproducts. (b) What is \(\Delta H\) for the formation of one mole of silicon? (c) Is the overall reaction exothermic?

A 12 -oz can of most colas has about 120 nutritional calories (1 nutritional calorie \(=1\) kilocalorie). Approximately how many minutes of walking are required to burn up as energy the calories taken in after drinking a can of cola? (Walking uses up about \(250 \mathrm{kcal} / \mathrm{h}\).)

Which statement(s) is/are true about bond enthalpy? (a) Energy is required to break a bond. (b) \(\Delta H\) for the formation of a bond is always a negative number. (c) Bond enthalpy is defined only for bonds broken or formed in the gaseous state. (d) Because the presence of \(\pi\) bonds does not influence the geometry of a molecule, the presence of \(\pi\) bonds does not affect the value of the bond enthalpy between two atoms either. (e) The bond enthalpy for a double bond between atoms \(A\) and \(B\) is twice that for a single bond between atoms \(\mathrm{A}\) and \(\mathrm{B}\).

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