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Consider three metals, \(\mathrm{X}, \mathrm{Y}\), and \(\mathrm{Z}\), and their salts, \(\mathrm{XA}, \mathrm{YA}\), and \(\mathrm{ZA}\). Three experiments take place with the following results: \- \(\mathrm{X}+\mathrm{hot} \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{H}_{2}\) bubbles \(\mathrm{X}+\mathrm{YA} \longrightarrow\) no reaction I \(\mathrm{X}+\mathrm{ZA} \longrightarrow \mathrm{X}\) discolored \(+\mathrm{Z}\) Rank metals \(\mathrm{X}, \mathrm{Y}\), and \(\mathrm{Z}\), in order of decreasing strength as reducing agents.

Short Answer

Expert verified
Question: Rank the metals X, Y, and Z in order of decreasing strength as reducing agents based on the given information from three experiments. Answer: X > Z > Y

Step by step solution

01

Analyzing the given information from three experiments

In the first experiment, X reacts with hot water to produce hydrogen bubbles. This tells us that X is a reactive metal, as it displaces hydrogen from water. In the second experiment, X does not react with YA, which suggests that X is less reactive than Y, as it cannot displace Y from its salt. In the third experiment, X reacts with ZA and forms X discolored and Z. This implies that X can displace Z from its salt and thus X is more reactive than Z.
02

Ranking the metals according to their reactivity#advice_likelihood#0.8advice_end

Based on the above analysis, the order of decreasing reactivity (or reducing strength) is: - X is more reactive than Y, so Y is the weakest reducing agent. - X is more reactive than Z, so X is the strongest reducing agent. - Z is in the middle, so Z is the intermediate reducing agent. Thus, the order of decreasing strength as reducing agents is X > Z > Y.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactivity
Chemical reactivity refers to the tendency of a substance to engage in chemical reactions. In the context of metals, reactivity can vary significantly across the periodic table. Highly reactive metals, such as those in the alkali and alkaline earth metal groups, can readily lose electrons to form positive ions. This property defines how a metal will react with substances like water, acids, and the components of salts.

Understanding the reactivity series is crucial for predicting outcomes of reactions. Metals higher in the series can displace those lower down from their compounds. In our exercise, the reactivity series helped determine that Metal X was able to displace hydrogen from water, indicating its high reactivity, while its failure to react with compound YA suggested it was less reactive than Metal Y.
Displacement Reactions
Displacement reactions are a type of chemical reaction where a more reactive element displaces a less reactive one from its compound. In the exercise, Metal X can replace Hydrogen in water, and displace Metal Z from ZA, but it cannot displace Metal Y from YA.

Through these observations, the reactivity ordering can be deduced. Displacement is a powerful tool in chemistry for extracting metals from their ores and in industrial applications where certain metals are purified by displacing them with others. These reactions are predictive when you know the reactivity series and are pivotal in understanding why certain metals are more suitable as reducing agents.
Reducing Agents
Reducing agents, or reducers, are substances that can donate electrons to other substances during a chemical reaction. Metals often serve as reducing agents due to their ability to lose electrons easily.

In redox reactions, the strength of a reducing agent is indicated by its willingness to lose electrons. Metals that lose electrons easily are considered good reducing agents. The exercise demonstrated that Metal X was the strongest reducing agent among the three because it could easily donate electrons to both hot water and Metal Z's salt. However, since it could not react with Metal Y's salt, it inferred that Metal Y was an even stronger reducing agent. This quality is fundamental in processes like electroplating, battery design, and metallurgy.

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Most popular questions from this chapter

Consider the following reaction at \(25^{\circ} \mathrm{C}\). $$ \mathrm{O}_{2}(g)+4 \mathrm{H}^{+}(a q)+4 \mathrm{Br}^{-}(a q) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{Br}_{2}(l) $$ If \(\left[\mathrm{H}^{+}\right]\) is adjusted by adding a buffer that is \(0.100 M\) in sodium acetate and \(0.100 \mathrm{M}\) in acetic acid, the pressure of oxygen gas is \(1.00 \mathrm{~atm}\), and the bromide concentration is \(0.100 \mathrm{M}\), what is the calculated cell voltage? ( \(K_{\mathrm{a}}\) acetic acid \(\left.=1.8 \times 10^{-5} .\right)\).

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In a nickel-cadmium battery (Nicad), cadmium is oxidized to \(\mathrm{Cd}(\mathrm{OH})_{2}\) at the anode, while \(\mathrm{Ni}_{2} \mathrm{O}_{3}\) is reduced to \(\mathrm{Ni}(\mathrm{OH})_{2}\) at the cathode. A portable CD player uses \(0.175\) amp of current. How many grams of \(\mathrm{Cd}\) and \(\mathrm{Ni}_{2} \mathrm{O}_{3}\) are consumed when the CD player is used for an hour and a half?

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