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Fill in the blanks in the following table. (a) \(\mathrm{CoCO}_{3}\) (b) \(\mathrm{LaF}_{3}\) (c) \(\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)

Short Answer

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Question: Identify the name, type, charges, and formula units for the following compounds: (a) CoCO3 (b) LaF3 (c) Ba3(PO4)2 Answer: (a) Cobalt(II) Carbonate, Ionic Compound, Co^2+ and CO3^2-, CoCO3 (b) Lanthanum(III) Fluoride, Ionic Compound, La^3+ and F^-, LaF3 (c) Barium Phosphate, Ionic Compound, Ba^2+ and PO4^3-, Ba3(PO4)2

Step by step solution

01

(a) CoCO3: Name of Compound

Cobalt(II) Carbonate
02

(a) CoCO3: Type of Compound

Ionic Compound
03

(a) CoCO3: Charges

Cobalt(II) has a charge of +2 (Co^2+), while carbonate (CO3) has a charge of -2 (CO3^2-).
04

(a) CoCO3: Formula Unit

As the charges balance each other out, the formula unit is CoCO3.
05

(b) LaF3: Name of Compound

Lanthanum(III) Fluoride
06

(b) LaF3: Type of Compound

Ionic Compound
07

(b) LaF3: Charges

Lanthanum(III) has a charge of +3 (La^3+), while fluoride (F) has a charge of -1 (F^-).
08

(b) LaF3: Formula Unit

To balance the charges, we need three fluoride ions for each lanthanum ion; the formula unit is LaF3.
09

(c) Ba3(PO4)2: Name of Compound

Barium Phosphate
10

(c) Ba3(PO4)2: Type of Compound

Ionic Compound
11

(c) Ba3(PO4)2: Charges

Barium (Ba) has a charge of +2 (Ba^2+), while phosphate (PO4) has a charge of -3 (PO4^3-).
12

(c) Ba3(PO4)2: Formula Unit

To balance the charges, we need three barium ions and two phosphate ions; the formula unit is Ba3(PO4)2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Nomenclature
Chemical nomenclature refers to the systematic naming of chemical compounds based on their molecular composition and structure. It plays a crucial role in ensuring clear communication within the scientific community and prevents misunderstandings. In the context of ionic compounds, each name consists of two parts:
  • The name of the metal (cation) comes first.
  • Followed by the name of the non-metal (anion) with a suffix change to "-ide" when the anion is a simple ion.
A more complex anion, such as a polyatomic ion, retains its name without changes. For example, the compound LaF3 is called lanthanum(III) fluoride. Here, "lanthanum(III)" indicates the +3 charge of lanthanum ions. Remember, Roman numerals denote the charge on transition metals since they can have different oxidation states. Knowing these naming conventions is fundamental as it helps us relate the compound's name to its chemical formula and vice versa. This understanding is crucial in writing and interpreting chemical equations clearly.
Chemical Formula
The chemical formula of a compound represents the types and numbers of atoms present. In ionic compounds, this formula also conveys information about the balance of charges. By understanding chemical formulas, we can deduce the compound's basic composition and its neutral charge state. For instance, with CoCO3:
  • Co represents cobalt, and CO3 is the carbonate ion.
  • Cobalt has a charge of +2, and carbonate has a charge of -2.
This balance results in the 1:1 ratio seen in CoCO3. The process of determining the correct chemical formula involves ensuring total positive and negative charges cancel each other out. For example, in Ba3(PO4)2, we have three barium ions (Ba) each with a +2 charge and two phosphate ions (PO4) each with a -3 charge. Balancing these charges is essential to accurately reflect the stoichiometry of the compound and is pivotal in further chemical analyses or reactions.
Ionic Bonds
Ionic bonds form through the electrostatic attraction between cations (positively charged ions) and anions (negatively charged ions). This type of chemical bond occurs when one atom transfers electrons to another, resulting in the formation of ions. For example, in lanthanum(III) fluoride (LaF3), lanthanum loses three electrons, becoming a cation (La3+), and each fluorine gains one electron, forming fluoride anions (F-). The attraction between the oppositely charged ions holds the compound together. Ionic bonds are generally strong, leading to compounds with high melting and boiling points and typically solid crystalline structures. Understanding ionic bonds is critical in predicting the properties of an ionic compound and explaining how such compounds will interact with others both chemically and physically.

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Most popular questions from this chapter

Calcium ions in blood trigger clotting. To prevent that in donated blood, sodium oxalate, \(\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), is added to remove calcium ions according to the following equation. $$ \mathrm{C}_{2} \mathrm{O}_{4}^{2-}(a q)+\mathrm{Ca}^{2+}(a q) \longrightarrow \mathrm{CaC}_{2} \mathrm{O}_{4}(s) $$ Blood contains about \(0.10 \mathrm{mg} \mathrm{Ca}^{2+} / \mathrm{mL}\). If a 250.0-mL sample of donated blood is treated with an equal volume of \(0.160 \mathrm{M} \mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\), estimate \(\left[\mathrm{Ca}^{2+}\right]\) after precipitation. \(\left(K_{s p} \mathrm{CaC}_{2} \mathrm{O}_{4}=4 \times 10^{-9}\right)\)

Shown below is a representation of the ionic solid \(\mathrm{MX}\), where \(\mathrm{M}\) cations are represented by squares and \(X\) anions are represented by circles. Fill in the box after the arrow to represent what happens to the solid after it has been completely dissolved in water. For simplicity, do not represent the water molecules.

Calculate the solubility (g/100 mL) of iron(II) hydroxide in buffered solutions with the following pH's. (a) 4 (b) 7 (c) 10

The box below represents one liter of a saturated solution of the species \(\square\), where squares represent the cation and circles represent the anion. Water molecules, though present, are not shown. Complete the next three figures below by filling one-liter boxes to the right of the arrow, showing the state of the ions after water is added to form saturated solutions. The species represented to the left of the arrow is the solid form of the ions represented above. Do not show the water molecules.

Lead azide, \(\mathrm{Pb}\left(\mathrm{N}_{3}\right)_{2}\), is used as a detonator in car airbags. The impact of a collision causes \(\mathrm{Pb}\left(\mathrm{N}_{3}\right)_{2}\) to be converted into an enormous amount of gas that fills the airbag. At \(25^{\circ} \mathrm{C}\), a saturated solution of lead azide is prepared by dissolving \(25 \mathrm{mg}\) in water to make \(100.0 \mathrm{~mL}\) of solution. What is \(K_{\mathrm{sp}}\) for lead azide?

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