Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Nitrosyl chloride (NOCl) decomposes to nitrogen oxide and chlorine gases. (a) Write a balanced equation using smallest whole-number coefficients for the decomposition. (b) Write an expression for the reaction rate in terms of \(\Delta[\mathrm{NOCl}] .\) (c) The concentration of NOCl drops from \(0.580 M\) to \(0.238 M\) in \(8.00 \mathrm{~min}\). Calculate the average rate of reaction over this time interval.

Short Answer

Expert verified
Question: Calculate the average rate of reaction for the decomposition of Nitrosyl chloride (NOCl) from an initial concentration of 0.580 M to a final concentration of 0.238 M over 8.00 minutes. Answer: The average rate of reaction for the decomposition of Nitrosyl chloride (NOCl) is approximately 7.13 x 10^-4 M/s.

Step by step solution

01

Write a Balanced Chemical Equation

First, we need to write a balanced chemical equation for the decomposition of Nitrosyl chloride (NOCl) into nitrogen oxide (NO) and chlorine gas (Cl2). The unbalanced equation for this reaction is: NOCl -> NO + Cl2 To balance the equation, we need to add a coefficient of 2 in front of NOCl: 2NOCl -> 2NO + Cl2 The balanced chemical equation is: 2NOCl -> 2NO + Cl2
02

Write an Expression for the Reaction Rate Based on the Change in Concentration of NOCl

The reaction rate is defined as the change in concentration of a reactant or product over a given time interval. Since NOCl is a reactant, the reaction rate will be the negative of the change in concentration of NOCl over the time interval: Reaction rate = -\(\frac{\Delta[\mathrm{NOCl}]}{\Delta t}\)
03

Calculate the Average Rate of Reaction Over the Given Time Interval

The concentration of NOCl drops from \(0.580 \ \text{M}\) to \(0.238 \ \text{M}\) during \(8.00 \ \text{min}\). We can calculate the average rate of reaction as follows: Average rate of reaction = -\(\frac{\Delta[\mathrm{NOCl}]}{\Delta t}\) = \(\frac{Initial \ NOCl \ Concentration - Final \ NOCl \ Concentration}{time}\) Average rate of reaction = \(\frac{0.580 \ \text{M} - 0.238 \ \text{M}}{8.00\ \text{min}}\) Now we convert the time to seconds: \(8.00 \ \text{min} = 8.00 \ \text{min} \times \frac{60 \ \text{s}}{1 \ \text{min}} = 480 \ \text{s}\) Average rate of reaction = \(\frac{0.580 \ \text{M} - 0.238 \ \text{M}}{480 \ \text{s}}\) Average rate of reaction ≈ \(\frac{0.342 \ \text{M}}{480 \ \text{s}} ≈ 7.13 \times 10^{-4} \ \text{M/s}\) So, the average rate of reaction for this decomposition is approximately \(7.13 \times 10^{-4} \ \text{M/s}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balanced Chemical Equation
Understanding a balanced chemical equation is crucial in the study of chemical reactions. It represents equal numbers of atoms for each element involved on both the reactant and product sides, adhering to the Law of Conservation of Mass.

To balance an equation, coefficients are added before chemical formulas to ensure that the number of atoms of each element is the same on both sides. In the decomposition of nitrosyl chloride (NOCl), we observe the equation is balanced by placing a coefficient of 2 in front of NOCl and the products, nitrogen oxide (NO), and chlorine gas (Cl2), to have equal numbers of nitrogen and chlorine atoms on both sides.

Example:

The balanced equation for the decomposition of NOCl is: ن لن نأتي ذلك، the allowance and delicate biscuits on. 2NOCl -> 2NO + Cl2. This correct representation is the foundation for understanding reaction stoichiometry, helping us to predict the amounts of each substance involved in the reaction process.
Reaction Rate
Reaction rate is a measure of how fast a chemical reaction occurs and is commonly expressed in terms of the change in concentration of a reactant or product per unit time. It can be affected by various factors including the concentration of reactants, temperature, and the presence of catalysts.

In practice, the rate at which a reactant decreases is represented with a negative sign as this indicates a reduction over time. For instance, the rate of decomposition of NOCl is defined as the negative change in concentration of NOCl over a change in time: ن أولًا نحتسب, Reaction rate = -\(\frac{\Delta[\mathrm{NOCl}]}{\Delta t}\). This formulation allows us to quantify the speed of the reaction and is essential in determining reaction kinetics, which in turn can be critical for controlling industrial chemical processes and understanding natural phenomena.
Concentration of Reactants
The concentration of reactants plays a pivotal role in affecting the rate of a chemical reaction. According to the collision theory of chemical kinetics, reactions occur when reactant molecules collide with sufficient energy and the correct orientation.

A higher concentration of reactants will result in more frequent collisions, which generally leads to an increased reaction rate. For example, as the concentration of nitrosyl chloride (NOCl) decreases, there are fewer NOCl molecules available to collide, which influences the reaction rate.

Therefore, it's important to monitor and control the concentrations of reactants in chemical reactions, especially in industrial production where the efficiency of the process may be affected by how quickly reactants are converted into products.
Average Rate of Reaction
The average rate of reaction provides a simplified view of the reaction rate over a specified time period, rather than its instantaneous rate at a particular moment. It is obtained by measuring the change in concentration of a reactant or product over the course of the reaction and dividing by the total reaction time.

In our example, the average rate of reaction was found by calculating how much the concentration of NOCl decreased during an 8-minute interval. This measure helped us understand the overall pace of the nitrosyl chloride decomposition without focusing on the variations that might occur at different moments within the time frame.

Calculation:

The formula for the average rate of reaction we used was: ن من القواعد الصورية للطاقة الشمسية, Average rate of reaction = -\(\frac{\Delta[\mathrm{NOCl}]}{\Delta t}\) = \(\frac{Initial \ NOCl \ Concentration - Final \ NOCl \ Concentration}{time}\), which provides a practical and understandable metric for the reaction's progress over time.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Diethylhydrazine reacts with iodine according to the following equation: $$\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2}(\mathrm{NH})_{2}(l)+\mathrm{I}_{2}(a q) \longrightarrow\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{~N}_{2}(l)+2 \mathrm{HI}(a q)$$ The rate of the reaction is followed by monitoring the disappearance of the purple color due to iodine. The following data are obtained at a certain temperature. $$ \begin{array}{cccc} \hline \text { Expt. } & {\left[\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2}(\mathrm{NH})_{2}\right]} & {\left[\mathrm{I}_{2}\right]} & \text { Initial Rate }(\mathrm{mol} / \mathrm{L} \cdot \mathrm{h}) \\ \hline 1 & 0.150 & 0.250 & 1.08 \times 10^{-4} \\ 2 & 0.150 & 0.3620 & 1.56 \times 10^{-4} \\ 3 & 0.200 & 0.400 & 2.30 \times 10^{-4} \\ 4 & 0.300 & 0.400 & 3.44 \times 10^{-4} \\ \hline\end{array}$$ (a) What is the order of the reaction with respect to diethylhydrazine, iodine, and overall? (b) Write the rate expression for the reaction. (c) Calculate \(k\) for the reaction. (d) What must \(\left[\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2}(\mathrm{NH})_{2}\right]\) be so that the rate of the reaction is \(5.00 \times 10^{-4} \mathrm{~mol} / \mathrm{L} \cdot \mathrm{h}\) when \(\left[\mathrm{I}_{2}\right]=0.500 ?\)

For the decomposition of HI, the activation energy is \(182 \mathrm{~kJ} / \mathrm{mol}\). The rate constant at \(850^{\circ} \mathrm{C}\) is \(0.0174 \mathrm{~L} / \mathrm{mol} \cdot \mathrm{h}\). (a) What is the rate constant at \(700^{\circ} \mathrm{C} ?\) (b) At what temperature will the rate constant be a fourth of what it is at \(850^{\circ} \mathrm{C} ?\)

Write the rate expression for each of the following elementary steps: (a) \(\mathrm{NO}_{3}+\mathrm{CO} \longrightarrow \mathrm{NO}_{2}+\mathrm{CO}_{2}\) (b) \(\mathrm{I}_{2} \longrightarrow 2 \mathrm{I}\) (c) \(\mathrm{NO}+\mathrm{O}_{2} \longrightarrow \mathrm{NO}_{3}\)

The reaction $$\mathrm{ICl}(g)+\frac{1}{2} \mathrm{H}_{2}(g) \longrightarrow \frac{1}{2} \mathrm{I}_{2}(g)+\mathrm{HCl}(g)$$ is first-order in both reactants. The rate of the reaction is \(4.89 \times 10^{-5} \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s}\) when the ICl concentration is \(0.100 M\) and that of the hydrogen gas is \(0.030 \mathrm{M}\) (a) What is the value of \(k\) ? (b) At what concentration of hydrogen is the rate \(5.00 \times 10^{-4} \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s}\) and \([\mathrm{ICl}]=0.233 \mathrm{M?}\) (c) At what concentration of iodine chloride is the rate \(0.0934 \mathrm{~mol} / \mathrm{L} \cdot \mathrm{s}\) if the hydrogen concentration is three times that of ICl?

At low temperatures, the rate law for the reaction $$\mathrm{CO}(\mathrm{g})+\mathrm{NO}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+\mathrm{NO}(g)$$ is as follows: rate \(=\) constant \(\times\left[\mathrm{NO}_{2}\right]^{2}\). Which of the following mechanisms is consistent with the rate law? (a) \(\mathrm{CO}+\mathrm{NO}_{2} \longrightarrow \mathrm{CO}_{2}+\mathrm{NO}\) (b) \(2 \mathrm{NO}_{2} \rightleftharpoons \mathrm{N}_{2} \mathrm{O}_{4} \quad\) (fast) \(\mathrm{N}_{2} \mathrm{O}_{4}+2 \mathrm{CO} \longrightarrow 2 \mathrm{CO}_{2}+2 \mathrm{NO} \quad\) (slow) (c) \(2 \mathrm{NO}_{2} \longrightarrow \mathrm{NO}_{3}+\) NO \(\quad\) (slow) \(\mathrm{NO}_{3}+\mathrm{CO} \longrightarrow \mathrm{NO}_{2}+\mathrm{CO}_{2} \quad\) (fast) (d) \(2 \mathrm{NO}_{2} \longrightarrow 2 \mathrm{NO}+\mathrm{O}_{2} \quad\) (slow) \(\mathrm{O}_{2}+2 \mathrm{CO} \longrightarrow 2 \mathrm{CO}_{2} \quad\) (fast)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free