The following equations are balanced in following manner:
(a)
\(Fe(s) + {H_2}O(g) \to F{e_3}{O_4}(s) + {H_2}(g)\)
After balancing the oxidation number and reduction number we have:
\(\begin{aligned}{l}O:3Fe \to 3F{e^{\frac{8}{3} + }} + 8{e^ - }\\R:8{H^ + } + 8{e^ - } \to 8H\\\overline {3Fe + 8{H^ + } \to 3F{e^{\frac{8}{3} + }} + 8H} \end{aligned}\)
From, that we have,
\(3Fe + 4{H_2}O(g) \to F{e_3}{O_4}(s) + 4{H_2}(g)\)
(b)
\(NaOH(aq) + Fe{(N{O_3})_3}(aq) \to Fe{(OH)_3}(s) + N{a^ + }(aq) + NO_3^ - (aq)\)
After balancing the oxidation number and reduction number we have:
\(3NaOH(aq) + Fe{(N{O_3})_3}(aq) \to Fe{(OH)_3}(s) + N{a^ + }(aq) + 3NO_3^ - (aq)\)
From, that we have,
\(3NaOH(aq) + Fe{(N{O_3})_3}(aq) \to Fe{(OH)_3}(s) + 3N{a^ + }(aq) + 3NO_3^ - (aq)\)
(c)
\(F{e^{2 + }}(s) + MnO_4^ - (aq) + {H^ + }(aq) \to F{e^{3 + }}(aq) + M{n^{2 + }}(aq) + {H_2}O(l)\)
After balancing the oxidation number and reduction number we have:
\(\begin{aligned}{l}O:5F{e^{2 + }} \to 5F{e^{3 + }} + 5{e^ - }\\R:MnO_4^ - + 5{e^ - } + 8{H^ + } \to M{n^{2 + }} + 4{H_2}O\\\overline {5F{e^{2 + }} + MnO_4^ - + 8{H^ + } \to 5F{e^{3 + }} + M{n^{2 + }} + 4{H_2}O(l)} \end{aligned}\)
From, that we have,
\(5F{e^{2 + }} + MnO_4^ - + 8{H^ + } \to 5F{e^{3 + }} + M{n^{2 + }} + 4{H_2}O(l)\)
(d)
\(Fe(s) + {H_3}{O^ + }(aq) + SO_4^{2 - }(aq) \to FeS{O_4}(aq) + {H_2}(g) + {H_2}O(l)\)
After balancing the oxidation number and reduction number we have:
\(\begin{aligned}{l}O:Fe \to F{e^{2 + }} + 2{e^ - }\\R:2{H^ + } + 2{e^ - } \to 2{H^0}\\F{e^ + } + 2{H^ + } \to F{e^{2 + }} + 2{H^0}\end{aligned}\)
From, that we have,
\(Fe(s) + 2{H_3}{O^ + }(aq) + SO_4^{2 - }(aq) \to FeS{O_4}(aq) + {H_2}(g) + 2{H_2}O(l)\)
(e)
\(F{e^{2 + }}(aq) + {O_2}(g) + HN{O_3}(aq) \to F{e^{3 + }}(aq) + NO_3^ - (aq) + {H_2}O(l)\)
After balancing the oxidation number and reduction number we have:
\(\begin{aligned}{l}O:4F{e^{2 + }} \to 4F{e^{3 + }} + 4{e^ - }\\R:2{O^0} + 4{e^ - } \to 2{O^{2 - }}\\4F{e^{2 + }} + 2{O^0} \to 4F{e^{3 + }} + 2{O^{2 - }}\end{aligned}\)
From, that we have,
\(4F{e^{2 + }}(aq) + {O_2}(g) + HN{O_3}(aq) \to 4F{e^{3 + }}(aq) + NO_3^ - (aq) + 2{H_2}O(l)\)
(f)
\(FeC{O_3}(s) + HCl{O_4}(aq) \to Fe{(Cl{O_4})_2}(aq) + C{O_2}(g) + {H_2}O(l)\)
From, that we have,
\(FeC{O_3}(s) + 2HCl{O_4}(aq) \to Fe{(Cl{O_4})_2}(aq) + C{O_2}(g) + {H_2}O(l)\)
(g)
\(Fe(s) + {O_2}(g) \to F{e_3}{O_4}(s)\)
After balancing the oxidation number and reduction number we have:
\(\begin{aligned}{l}O:3Fe \to 3F{e^{\frac{8}{3} + }} + 8{e^ - }\\R:2{O^0} + 4{e^ - } \to 2{O^{2 - }}\\\overline {3Fe + 4{O^0} \to 3F{e^{\frac{8}{3} + }} + 4{O^{2 - }}} \end{aligned}\)
From, that we have,
\(3Fe(s) + 2{O_2}(g) \to F{e_3}{O_4}(s)\)
Hence, the final answer is,
The balanced reactions are as follow:
a)\(3Fe + 4{H_2}O(g) \to F{e_3}{O_4}(s) + 4{H_2}(g)\)
b)\(3NaOH(aq) + Fe{(N{O_3})_3}(aq) \to Fe{(OH)_3}(s) + 3N{a^ + }(aq) + 3NO_3^ - (aq)\)
c)\(5F{e^{2 + }} + MnO_4^ - + 8{H^ + } \to 5F{e^{3 + }} + M{n^{2 + }} + 4{H_2}O(l)\)
d)\(Fe(s) + 2{H_3}{O^ + }(aq) + SO_4^{2 - }(aq) \to FeS{O_4}(aq) + {H_2}(g) + 2{H_2}O(l)\)
e)\(4F{e^{2 + }}(aq) + {O_2}(g) + HN{O_3}(aq) \to 4F{e^{3 + }}(aq) + NO_3^ - (aq) + 2{H_2}O(l)\)
f)\(FeC{O_3}(s) + 2HCl{O_4}(aq) \to Fe{(Cl{O_4})_2}(aq) + C{O_2}(g) + {H_2}O(l)\)
g) \(3Fe(s) + 2{O_2}(g) \to F{e_3}{O_4}(s)\)
