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Question: If 14.5 kJ of heat were added to 485 g of liquid water, how much would its temperature increase?

Short Answer

Expert verified

The rise in the temperature of water = \({7.14^0}C\).

Step by step solution

01

Specific heat

The heat required to raise the temperature of a substance is given by the formula Q = C × m ×∆T,

Where “C” is the specific heat of the substance, “m” is the mass of the substance, and “∆T” is the change in the temperature of the substance.

02

Increase in temperature

We know from the given details that:

C = 4.184 J/g °C(Table 5.1)

m = 485 g

Q = 14.5kJ = 14500 J

By putting the values above in the equation Q = C × m ×∆ T , we get:

14500 = 4.184 \( \times \) 485 \( \times \)\(\Delta \)T.

\(\Delta \)T = \(\frac{{14500}}{{4.184 \times 485}} = {7.14^0}C\).

Therefore, the rise in the temperature of 485 g of water = \({7.14^0}C\).

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Most popular questions from this chapter

If the 3.21g of NH4NO3 in example 5.6 were dissolved in 100.0g of water under the same conditions, how much would the temperature change? Explain your answer.

When 0.963 g of glucose, C6H6, is burned in a bomb calorimeter, the temperature of the calorimeter increases by 8.39°C. The bomb has a heat capacity of 784 J/°C and is submerged in 925 mL of water. How much heat was produced by the combustion of the glucose sample?

Water gas, a mixture of \({{\bf{H}}_{\bf{2}}}\) and CO, is an important industrial fuel produced by the reaction of steam with red hot coke, essentially pure carbon:\({\bf{C}}\left( {\bf{s}} \right){\bf{ + }}{{\bf{H}}_{\bf{2}}}{\bf{O}}\left( {\bf{g}} \right) \to {\bf{CO}}\left( {\bf{g}} \right){\bf{ + }}{{\bf{H}}_{\bf{2}}}\left( {\bf{g}} \right)\).

(a) Assuming that coke has the same enthalpy of formation as graphite, calculate \({\bf{\Delta H}}_{{\bf{298}}}^{\bf{0}}\)for this reaction.

(b) Methanol, a liquid fuel that could possibly replace gasoline, can be prepared from water gas and additional hydrogen at high temperature and pressure in the presence of a suitable catalyst:\({\bf{2}}{{\bf{H}}_{\bf{2}}}\left( {\bf{g}} \right){\bf{ + CO}}\left( {\bf{g}} \right) \to {\bf{C}}{{\bf{H}}_{\bf{3}}}{\bf{OH}}\left( {\bf{g}} \right)\).

Under the conditions of the reaction, methanol forms as a gas. Calculate \({\bf{\Delta H}}_{{\bf{298}}}^{\bf{0}}\)for this reaction and for the condensation of gaseous methanol to liquid methanol.

(c) Calculate the heat of combustion of 1 mole of liquid methanol to H2O(g) and CO2(g).

Dissolving 3.0 g of CaCl2(s) in 150.0 g of water in a calorimeter (Figure 5.12) at 22.4°C causes the temperature to rise to 25.8°C. What is the approximate amount of heat involved in the dissolution, assuming the heat capacity of the resulting solution is 4.18 J/g°C? Is the reaction exothermic or endothermic?

Calculate the enthalpy of solution (∆H) for the dissolution) per mole of NH4NO3 under the conditions described in example 5.6.

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