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Chapter 5: Q43 E (page 271)

Calculate the enthalpy of solution (∆H for the dissolution) per mole of CaCl2(refer to Exercise 5.25).

Short Answer

Expert verified

The enthalpy of a solution (∆H for the dissolution) per mole of CaCl2 is 81 kJ/mol.

Step by step solution

01

Given data

The molar mass of CaCl2 = 110.98 g/mol.

Mass of CaCl2 = 3.0g.

\begin{aligned}{\rm{NumberofmolesofCaC}}{{\rm{l}}_{\rm{2}}}{\rm{=}}\frac{{{\rm{givenmass\;}}}}{{{\rm{molarmass}}}}{\rm{\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;}}\\{\rm{=}}\frac{{{\rm{3}}{\rm{.0g}}}}{{{\rm{110}}{\rm{.98g/mol}}}}{\rm{\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;}}\\\end{aligned}

\begin{aligned}{\rm{=0}}{\rm{.0270 mol}}\end{aligned}

02

Enthalpy of a solution

The formula for finding the enthalpy of a solution is given below:

\[{\bf{Enthalpy=}}\frac{{{\bf{Heat of the solution}}}}{{{\bf{Number of moles}}}}\]

The known values are substituted:

\begin{aligned}{\rm{Enthalpy=}}\frac{{{\rm{2}}{\rm{.2kJ}}}}{{{\rm{0}}{\rm{.0270mol}}}}{\rm{\;}}\\{\rm{=81kJ/mol}}\end{aligned}

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Most popular questions from this chapter

Using the data in Appendix G, calculate the standard enthalpy change for each of the following reactions:

(a) N2(g) + O2(g)⟶2NO(g)

(b) Si(s) + 2Cl2(g)⟶SiCl4(g)

(c) Fe2O3(s) + 3H2(g)⟶2Fe(s) + 3H2O(l)

(d) 2LiOH(s) + CO2(g)⟶Li2CO3(s) + H2O(g)

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How much heat is evolved in the production of exactly 1 mole of \({\bf{Ti}}{{\bf{O}}_{\bf{2}}}\)(s) under standard state conditions?

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