Question

Short answer

∆H in kJ/mol of AgNO₃(aq) in the reaction :

NaCl(aq)+AgNO₃(aq)→ AgCl(s)+NaNO₃ (aq) is -67kJ/mol

Step-by-step solution

Given data

Data we are provided with:

100ml of 0.200M NaCl is mixed with 100ml of 0.200M AgNO₃.

The heat of thereaction is, q_reaction = -1.34k J.

Calculation of enthalpy change

The number of moles of NaCl = 0.200 × 0.1 L = 0.02 mol

The number of moles of AgNO₃ = 0.200 × 0.1 L = 0.02 mol

Hence, ∆H = -67 kJ/mol.

Therefore, enthalpy change when 1 mol of AgNO₃(aq) reacts is:

\begin{aligned}Enthalpychange=\frac{-1.34kJ}{0.02mol}=-67J/mol\end{aligned}