Question

What is the expected electrical conductivity of the following solutions?

1. \({\bf{NaOH}}\)(aq)
2. \({\bf{HCl}}\)(aq)
3. \({\bf{C}}_6{\bf{H}}_12{\bf{O}}_6\)(aq)(glucose)
4. \({\bf{NH}}_3\)(l).

Short answer

1. \({\rm{NaOH}}\)(aq.) does conduct electricity in ionic form. As it is a polar molecule
2. \({\rm{HCl}}\)(aq.) does conduct electricity in ionic form. It is a polar molecule.
3. \({\rm{C_6H_12O_6}}\)(aq.) does not conduct electricity in ionic form. It is a non-polar molecule.
4. \({\rm{NH_3}}\) (l) does not conduct electricity very well even in ionic form. It is a non-polar molecule\(\)

Step-by-step solution

Electrical Conductivity

Electrical conductivity is nothing but the measure of the capability of the material to pass theflow of electric currentthrough it and they flow of electrons form the electricity in the solution.

(a) Electrical conductivity of NaOH (aq)

\({\rm{NaOH}}\)(aq.) conduct electricity in solution form. It conducts electricity due to the formation of ions. The molecule is polar and can dissolve in ionic solvent.

\({\rm{NaOH }}\left( {{\rm{aq}}} \right){\rm{ }} \to {\rm{ N}}{{\rm{a}}^{\rm{ + }}}{\rm{ + O}}{{\rm{H}}^{\rm{ - }}}\) \(\)

(b) Electrical conductivity of NaOH (aq)

\({\rm{HCl}}\)(aq.) conduct electricity due to the formation of electricity due to the formation of ions. In the solution form, they form ions as they are polar molecule.

\({\rm{HCl}}\left( {{\rm{aq}}{\rm{.}}} \right){\rm{ }} \to {\rm{ }}{{\rm{H}}^{\rm{ + }}}{\rm{ + C}}{{\rm{l}}^{\rm{ - }}}\)

(c) Electrical conductivity of NaOH (aq)

\({\rm{C_6H_12O_6}}\) (aq) is a organic compound which does not conduct electricity as it does not form ions. It is very un-capable of forming ions and does not dissolve in ionic form.

(d) Electrical conductivity of NaOH (aq)

\({\rm{NH_3}}\)(l) is a organic molecules which does not conduct electricity as it does not form ions . The molecule form ions but they are fewer in number.