Question

Give the hybridization and oxidation state for sulfur in$\mathrm{S}{\mathrm{O}}_2$, in$\mathrm{S}{\mathrm{O}}_3$, and in${\mathrm{H}}_2\mathrm{S}{\mathrm{O}}_4$.

Short answer

Therefore,

1. The oxidation number of is$+4$.
2. The oxidation number of$\mathrm{S}{\mathrm{O}}_3$is$+6$.
3. The oxidation number of ${\mathrm{H}}_2\mathrm{S}{\mathrm{O}}_4$is $+6$.

Step-by-step solution

What is the oxidation state of $\mathrm{S}{\mathrm{O}}_2$.

a) In$\mathrm{S}{\mathrm{O}}_2$the oxidation number of oxygen is$-2$.

So, the oxidation number of sulfur is $+4$.

$s{p}^2$hybridization

What is the oxidation state of .

b) In$\mathrm{S}{\mathrm{O}}_3$the oxidation number of oxygen is$-2$.

So, the oxidation number of sulfur is $+6$.

$s{p}^2$hybridization

What is the oxidation state of ${\mathrm{H}}_2\mathrm{S}{\mathrm{O}}_4$.

c) In${\mathrm{H}}_2\mathrm{S}{\mathrm{O}}_4$the oxidation number of hydrogen is$+1$, while oxygen is$-2$.

So, the oxidation number of sulfur is $+6$.

$s{p}^3$hybridization