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In drawing Lewis structures, we learn that a hydrogen atom forms only one bond in a covalent compound. Why?

Short Answer

Expert verified

Since a hydrogen atom has only one electron, it can make only one bond with another element. Its oxidation state can be either be -1, 0,or +1 depending onwhether the hydrogen receives, shares, or loses an electron.

Step by step solution

01

Definition of Lewis structures

The Lewis structures, also known as the Lewis dot formulas,are diagrams that show the bonding between the atoms of a molecule as well as the lone pairs of an electron that may exist in a molecule.

02

Reason why hydrogen forms only one bond

When the electronegativity of atoms is similar, an electron pair that isshared is equally attracted by both atoms, making this covalent bond non-polar.

The difference in the electronegativity of the two atoms is less than 0.5. However, when two atoms differ in their electronegativity by more than 0.5 but upto 1.7, an electron pair is closer to the atom with a higher value of electronegativity,so this covalent bond is polar.

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Most popular questions from this chapter

Give the hybridization of the metalloid and the molecular geometry for each of the following compounds or ions. You may wish to review the chapters on chemical bonding and advanced covalent bonding for relevant examples.

\((a){\rm{Ge}}{{\rm{H}}_4}\)

\((b){\rm{Sb}}{{\rm{F}}_3}\)

\((c){\rm{Te}}{({\rm{OH}})_6}\)

\((d){{\rm{H}}_2}{\rm{Te}}\)

\((e){\rm{Ge}}{{\rm{F}}_2}\)

\((f){\rm{TeC}}{{\rm{l}}_4}\)

\((g){\rm{SiF}}_6^{2 - }\)

\((h){\rm{SbC}}{{\rm{l}}_5}\)

\((i){\rm{Te}}{{\rm{F}}_6}\)

Describe the hybridization of phosphorus in each of the following compounds: \({{\rm{P}}_4}{{\rm{O}}_{10}},{{\rm{P}}_4}{{\rm{O}}_6},{\rm{P}}{{\rm{H}}_4}{\rm{I}}\) (an ionic compound), \({\rm{PB}}{{\rm{r}}_3},{{\rm{H}}_3}{\rm{P}}{{\rm{O}}_4},{{\rm{H}}_3}{\rm{P}}{{\rm{O}}_3},{\rm{P}}{{\rm{H}}_3}\) and\({{\rm{P}}_2}{{\rm{H}}_4}\). You may wish to review the chapter on advanced theories of covalent bonding.

A chemist dissolves a \({\bf{1}}.{\bf{497}} - {\bf{g}}\) sample of a type of metal (an alloy of \({\bf{Sn}},{\rm{ }}{\bf{Pb}},{\rm{ }}{\bf{Sb}},\)and\({\bf{Cu}}\)) in nitric acid, and metastannic acid,\({{\bf{H}}_2}{\bf{Sn}}{{\bf{O}}_3}\), is precipitated. She heats the precipitate to drive off the water, which leaves \({\bf{0}}.{\bf{4909}}\)g of tin (IV) oxide. What was the percentage of tin in the original sample?

The electrolysis of molten sodium chloride or of aqueous sodium chloride produces chlorine. Calculate the mass of chlorine produced from 3.00 kg sodium chloride in each case. You may wish to review the chapter on electrochemistry for relevant examples.

How many tons of \(C{a_3}{\left( {P{O_4}} \right)_2}\)are necessary to prepare 5.0 tons of phosphorus if the yield is 90 % ?

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