Chapter 18: Q22E (page 1040)
Why is it possible for an active metal like aluminium to be useful as a structural metal?
The formation of aprotective coating on metal surface is referred to as passivation. This is the reason that helps an active metal like aluminium to be useful as a structural metal.
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Name each of the following compounds:
\((a){\rm{Te}}{{\rm{O}}_2}\)
\((b){\rm{S}}{{\rm{b}}_2}\;{{\rm{S}}_3}\)
\((c){\rm{Ge}}{{\rm{F}}_4}\)
\((d){\rm{Si}}{{\rm{H}}_4}\)
\((e){\rm{Ge}}{{\rm{H}}_4}\)
What volume of \(0.200MNaOH\)is necessary to neutralize the solution produced by dissolving \(2.00\;{g^{g }}PC{l_3}\) is an excess of water? Note that when \({H_3}P{O_3}\)is titrated under these conditions, only one proton of the acid molecule reacts.
The reaction of calcium hydride,\({\rm{Ca}}{{\rm{H}}_{\rm{2}}}\), with water can be characterized as a Lewis acid-base reaction: \({\rm{Ca}}{{\rm{H}}_{\rm{2}}}\left( {\rm{s}} \right){\rm{ + 2}}{{\rm{H}}_{\rm{2}}}{\rm{O}}\left( {\rm{l}} \right) \to {\rm{Ca}}{\left( {{\rm{OH}}} \right)_{\rm{2}}}\left( {{\rm{aq}}} \right){\rm{ + 2}}{{\rm{H}}_{\rm{2}}}\left( {\rm{g}} \right)\).
Identify the Lewis acid and the Lewis base among the reactants. The reaction is also an oxidation-reduction reaction. Identify the oxidizing agent, the reducing agent, and the changes in oxidation number that occur in the reaction.
A hydride of silicon prepared by the reaction of \({\rm{M}}{{\rm{g}}_2}{\rm{Si}}\) with acid exerted a pressure of 306 torr at \({26^\circ }{\rm{C}}v\)in a bulb with a volume of\(57.0\;{\rm{mL}}\). If the mass of the hydride was\(0.0861\;{\rm{g}}\), what is its molecular mass? What is the molecular formula for the hydride?
Write balanced chemical equations for the following reactions:
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