Question

What is the hybridization of iodine in\({\rm{I}}{{\rm{F}}_3}\)and \({\rm{I}}{{\rm{F}}_5}\)?

Short answer

The hybridization of Iodine in \(I{F_3}\)is \(s{p^3}d\) and the \(I{F_5}\)is \(s{p^3}{d^2}\) respectively.

Step-by-step solution

Step 1:Concept of Hybridization

Hybridization is defined as an idea of mixing two atomic orbitals to give rise to a new type of hybridized orbitals which are comparable in energy.

The Hybridization of iodine in \(I{F_3}\).  

The \(I{F_3}\) is \(s{p^3}d\) hybridized.

The Hybridization of iodine in \(I{F_5}\).

The hybridization of \(I{F_5}\) is \(s{p^3}{d^2}\).