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Write the rate equation for each of the following elementary reactions:

\((a){\text{ }}{O_3}{\text{ }}\underrightarrow {sunlight}{\text{ }}{O_2}{\text{ }} + {\text{ }}O\).

\(\begin{array}\(b){\rm{ }}{O_3}{\rm{ }} + {\rm{ }}Cl{\rm{ }} \to {\rm{ }}{O_2}{\rm{ }} + {\rm{ }}ClO\\(c){\rm{ }}ClO{\rm{ }} + {\rm{ }}O{\rm{ }} \to {\rm{ }}Cl{\rm{ }} + {\rm{ }}{O_2}\\(d){\rm{ }}{O_3}{\rm{ }} + {\rm{ }}NO{\rm{ }} \to {\rm{ }}N{O_2}{\rm{ }} + {\rm{ }}{O_2}\\(e){\rm{ }}N{O_2}{\rm{ }} + {\rm{ }}O{\rm{ }} \to {\rm{ }}NO{\rm{ }} + {\rm{ }}{O_2}\end{array}\)

Short Answer

Expert verified

The rate equations for the following elementary reactions are:

\((a){\text{ }}{O_3}{\text{ }}\underrightarrow {sunlight}{\text{ }}{O_2}{\text{ }} + {\text{ }}O\)

\({\bf{rate = k[}}{{\bf{O}}_{\bf{3}}}{\bf{]}}\)

\(\begin{align}{\bf{(b) }}{{\bf{O}}_{\bf{3}}}{\bf{ + Cl }} \to {\bf{ }}{{\bf{O}}_{\bf{2}}}{\bf{ + ClO}}\\{\bf{rate = k(}}{{\bf{O}}_{\bf{3}}}{\bf{)(Cl)}}\end{align}\)

\(\begin{align}{\bf{(c) ClO + O }} \to {\bf{ Cl + }}{{\bf{O}}_{\bf{2}}}\\{\bf{rate = k(ClO)(O)}}\end{align}\)

\(\begin{align}{\bf{(d) }}{{\bf{O}}_{\bf{3}}}{\bf{ + NO }} \to {\bf{ N}}{{\bf{O}}_{\bf{2}}}{\bf{ + }}{{\bf{O}}_{\bf{2}}}\\{\bf{rate = k(}}{{\bf{O}}_{\bf{3}}}{\bf{)(NO)}}\end{align}\)

\(\begin{align}{\bf{(e) N}}{{\bf{O}}_{\bf{2}}}{\bf{ + O }} \to {\bf{ NO + }}{{\bf{O}}_{\bf{2}}}\\{\bf{rate = k(N}}{{\bf{O}}_{\bf{2}}}{\bf{)(O)}}\end{align}\)

Step by step solution

01

Definition of Rate Equation

The rate equation is the mathematical expression which explains the the relationship between the rate of a chemical reaction and the concentration of its reactants.

\({\bf{rate = k(A}}{{\bf{)}}^{\bf{x}}}{{\bf{(B)}}^{\bf{y}}}{{\bf{(C)}}^{\bf{z}}}.....\)

Where,

(A), (B), and (C) denotes the molar concentrations of reactants.

kis the rate constant.

Exponents m, n, and pare generally positive integers.

02

Rate Equations for the Elementary Reactions    

For the elementary reaction (a), the reaction is first order with respect to \({{\rm{O}}_{\rm{3}}}\), thus the rate equation will be:

\((a){\text{ }}{O_3}{\text{ }}\underrightarrow {sunlight}{\text{ }}{O_2}{\text{ }} + {\text{ }}O\)

\({\bf{rate = k[}}{{\bf{O}}_{\bf{3}}}{\bf{]}}\)

For the elementary reaction (b), the reaction is first order with respect to\({{\rm{O}}_{\rm{3}}}\) and \({\rm{Cl}}\)thus the rate equation will be:

\(\begin{align}{\bf{(b) }}{{\bf{O}}_{\bf{3}}}{\bf{ + Cl }} \to {\bf{ }}{{\bf{O}}_{\bf{2}}}{\bf{ + ClO}}\\{\bf{rate = k(}}{{\bf{O}}_{\bf{3}}}{\bf{)(Cl)}}\end{align}\)

For the elementary reaction (c), the reaction is first order with respect to \({\rm{ClO}}\) and \({\rm{O}}\)thus the rate equation will be:

\(\begin{align}{\bf{(c) ClO + O }} \to {\bf{ Cl + }}{{\bf{O}}_{\bf{2}}}\\{\bf{rate = k(ClO)(O)}}\end{align}\)

For the elementary reaction (d), the reaction is first order with respect to \({{\rm{O}}_{\rm{3}}}\) and \({\rm{NO}}\)thus the rate equation will be:

\(\begin{align}{\bf{(d) }}{{\bf{O}}_{\bf{3}}}{\bf{ + NO }} \to {\bf{ N}}{{\bf{O}}_{\bf{2}}}{\bf{ + }}{{\bf{O}}_{\bf{2}}}\\{\bf{rate = k(}}{{\bf{O}}_{\bf{3}}}{\bf{)(NO)}}\end{align}\)

For the elementary reaction (e), the reaction is first order with respect to \({\rm{N}}{{\rm{O}}_2}\) and \({\rm{O}}\)thus the rate equation will be:

\(\begin{align}{\bf{(e) N}}{{\bf{O}}_{\bf{2}}}{\bf{ + O }} \to {\bf{ NO + }}{{\bf{O}}_{\bf{2}}}\\{\bf{rate = k(N}}{{\bf{O}}_{\bf{2}}}{\bf{)(O)}}\end{align}\)

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Most popular questions from this chapter

Use the PhET Reactions & Rates interactive simulation (http://openstaxcollege.org/l/ 16PHETreaction) to simulate a system. On the โ€œSingle collisionโ€ tab of the simulation applet, enable the โ€œEnergy viewโ€ by clicking the โ€œ+โ€ icon. Select the first A + BCโŸถAB + C reaction (A is yellow, B is purple, and C is navy blue). Using the โ€œangled shotโ€ option, try launching the A atom with varying angles, but with more Total energy than the transition state. Whathappenswhen the A atom hitstheBC molecule from different directions? Why?

Use the provided initial rate data to derive the rate law for the reaction whose equation is: \({\bf{OC}}{{\bf{l}}^ - }\)(aq) + \({{\bf{I}}^ - }\)(aq) โŸถOIโˆ’(aq) +\({\bf{C}}{{\bf{l}}^ - }\)(aq)

Trial

(\({\bf{OC}}{{\bf{l}}^ - }\)) (mol/L)

(\({{\bf{I}}^ - }\)) (mol/L)

Initial Rate (mol/L/s)

1.

0.0040

0.0020

0.00184

2.

0.0020

0.0040

0.00092

3.

0.0020

0.0020

0.00046

Determine the rate law expression and the value of the rate constant k with appropriate units for this reaction.

The reaction of compound A to give compounds C and D was found to be second-order in A. The rate constant for the reaction was determined to be 2.42 L/mol/s. If the initial concentration is 0.500 mol/L, what is the value of t1/2?

Alcohol is removed from the bloodstream by a series of metabolic reactions. The first reaction produces acetaldehyde; then other products are formed. The following data have been determined for the rate at which alcohol is removed from the blood of an average male, although individual rates can vary by 25โ€“30%. Women metabolize alcohol a little more slowly than men:

Determine the rate equation, the rate constant, and the overall order for this reaction.

The half-life of a reaction of compound A to give compounds D and E is 8.50 min when the initial concentration of A is 0.150 mol/L. How long will it take for the concentration to drop to 0.0300 mol/L if the reaction is (a) first order with respect to A or (b) second order with respect to A?

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