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What is the rate equation for the elementary termolecular reaction A + 2B⟶products? For 3A⟶products?

Short Answer

Expert verified

For any reaction, the rate is given by the product of the concentration of the reactant, where each reactant concentration is raised to the power of the stoichiometric ratio.

Step by step solution

01

Termolecular reaction

For elementary termolecular reaction \({\bf{A + 2B}} \to {\bf{products}}\).

\({\bf{Rate = }}\left( {\bf{A}} \right){\left( {\bf{B}} \right)^{\bf{2}}}\).

Each concentration term in the rate equation is raised to the power equivalent to the stoichiometry of the particular reactant.

02

Rate of Termolecular reaction involving same reactants

For elementary reaction \({\bf{3A}} \to {\bf{products}}\), the rate of reaction is given by

\({\bf{Rate = }}{\left( {\bf{A}} \right)^{\bf{3}}}\)

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Most popular questions from this chapter

The hydrolysis of the sugar sucrose to the sugars glucose and fructose, \({{\bf{C}}_{{\bf{12}}}}{{\bf{H}}_{{\bf{22}}}}{{\bf{O}}_{{\bf{11}}}}{\bf{ + }}{{\bf{H}}_{\bf{2}}}{\bf{O}} \to {{\bf{C}}_{\bf{6}}}{{\bf{H}}_{{\bf{12}}}}{{\bf{O}}_{\bf{6}}}{\bf{ + }}{{\bf{C}}_{\bf{6}}}{{\bf{H}}_{{\bf{12}}}}{{\bf{O}}_{\bf{6}}}\) follows a first-order rate equation for the disappearance of sucrose: \({\bf{Rate = k}}\left( {{{\bf{C}}_{{\bf{12}}}}{{\bf{H}}_{{\bf{22}}}}{{\bf{O}}_{{\bf{11}}}}} \right)\) (The products of the reaction, glucose and fructose, have the same molecular formulas but differ in the arrangement of the atoms in their molecules.)

  1. In neutral solution, \({\bf{k = 2}}{\bf{.1 \times 1}}{{\bf{0}}^{{\bf{ - 11}}}}{{\bf{s}}^{{\bf{ - 1}}}}\) at 27 °C and \({\bf{8}}{\bf{.5 \times 1}}{{\bf{0}}^{{\bf{ - 11}}}}{{\bf{s}}^{{\bf{ - 1}}}}\) at 37 °C. Determine the activation energy, the frequency factor, and the rate constant for this equation at 47 °C (assuming the kinetics remain consistent with the Arrhenius equation at this temperature).
  2. When a solution of sucrose with an initial concentration of 0.150 M reaches equilibrium, the concentration of sucrose is\({\bf{1}}{\bf{.65 \times 1}}{{\bf{0}}^{{\bf{ - 7}}}}{\bf{ M}}\). How long will it take the solution to reach equilibrium at 27 °C in the absence of a catalyst? Because the concentration of sucrose at equilibrium is so low, assume that the reaction is irreversible.
  3. Why does assuming that the reaction is irreversible simplify the calculation in part (b)?

Determine which of the two diagrams here (both for the same reaction) involves a catalyst, and identify the activation energy for the catalyzed reaction:

Based on the diagrams in Exercise 12.83, which of the reactions has the fastest rate? Which has the slowest rate?

What is the difference between average rate, initial rate, and instantaneous rate?

Consider the following reaction in aqueous solution:

\(\)

\({\bf{5B}}{{\bf{r}}^ - }\left( {aq} \right) + BrO_3^ - \left( {aq} \right) + 6{H^ + }\left( {aq} \right) \to 3B{r_2}\left( {aq} \right) + 3{H_2}O\left( l \right)\)

If the rate of disappearance of Br (aq) at a particular moment during the reaction is 3.5 × 10−4 M s −1, what is the rate of appearance of\({\bf{B}}{{\bf{r}}_{\bf{2}}}\)(aq) at that moment?

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