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Chemical reactions occur when reactants collide. What are two factors that may prevent a collision from producing a chemical reaction?

Short Answer

Expert verified

Collision theory is a theory that is used to predict the rates of chemical reactions, particularly those involving gases. The collision theory holds that for a reaction to take place, the reacting species (atoms or molecules) must come into contact with one another.

Collision theory is founded on the following premises:

The reacting species must collide in such a way that contact between the atoms that will become bonded together in the product is possible.

The collision must have enough energy to allow mutual penetration of the valence of the reacting species. Shells, allowing electrons to rearrange and form new bonds (and new chemical species).

Step by step solution

01

Reaction of carbon monoxide with oxygen

Carbon monoxide is a pollutant that is produced during the combustion of hydrocarbon fuels. Automobiles have catalytic converters that use a catalyst to carry out this reaction to reduce this pollutant. It is also a byproduct of gunpowder combustion that causes muzzle flash in many firearms. At high temperatures and pressure, the reaction is spontaneous if sufficient amounts of carbon monoxide and oxygen are present.

The collision of two molecules is the first step in the gas-phase reaction of carbon monoxide and oxygen:

\({\bf{CO}}\left( {\bf{g}} \right){\bf{ + }}{{\bf{O}}_{\bf{2}}}\left( {\bf{g}} \right) \to {\bf{C}}{{\bf{O}}_{\bf{2}}}\left( {\bf{g}} \right){\bf{ + O}}\left( {\bf{g}} \right)\)

In the primary case, the oxygen aspect of the carbon monoxide molecule collides with the oxygen molecule.

02

Formation of carbon dioxide

In the second case, the carbon aspect of the carbon monoxide molecule collides with the oxygen molecule. The second case truly favors the formation of carbon dioxide (O = C = O), which has a crucial carbon atom bonded to 2 oxygen atoms. This is an easy example of ways critical collision orientation is in generating the favored response product. Two possible collisions between carbon monoxide and oxygen molecules. The orientation of the colliding molecules influences whether or not a reaction between the two molecules occurs.

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Most popular questions from this chapter

The hydrolysis of the sugar sucrose to the sugars glucose and fructose, \({{\bf{C}}_{{\bf{12}}}}{{\bf{H}}_{{\bf{22}}}}{{\bf{O}}_{{\bf{11}}}}{\bf{ + }}{{\bf{H}}_{\bf{2}}}{\bf{O}} \to {{\bf{C}}_{\bf{6}}}{{\bf{H}}_{{\bf{12}}}}{{\bf{O}}_{\bf{6}}}{\bf{ + }}{{\bf{C}}_{\bf{6}}}{{\bf{H}}_{{\bf{12}}}}{{\bf{O}}_{\bf{6}}}\) follows a first-order rate equation for the disappearance of sucrose: \({\bf{Rate = k}}\left( {{{\bf{C}}_{{\bf{12}}}}{{\bf{H}}_{{\bf{22}}}}{{\bf{O}}_{{\bf{11}}}}} \right)\) (The products of the reaction, glucose and fructose, have the same molecular formulas but differ in the arrangement of the atoms in their molecules.)

  1. In neutral solution, \({\bf{k = 2}}{\bf{.1 \times 1}}{{\bf{0}}^{{\bf{ - 11}}}}{{\bf{s}}^{{\bf{ - 1}}}}\) at 27 ยฐC and \({\bf{8}}{\bf{.5 \times 1}}{{\bf{0}}^{{\bf{ - 11}}}}{{\bf{s}}^{{\bf{ - 1}}}}\) at 37 ยฐC. Determine the activation energy, the frequency factor, and the rate constant for this equation at 47 ยฐC (assuming the kinetics remain consistent with the Arrhenius equation at this temperature).
  2. When a solution of sucrose with an initial concentration of 0.150 M reaches equilibrium, the concentration of sucrose is\({\bf{1}}{\bf{.65 \times 1}}{{\bf{0}}^{{\bf{ - 7}}}}{\bf{ M}}\). How long will it take the solution to reach equilibrium at 27 ยฐC in the absence of a catalyst? Because the concentration of sucrose at equilibrium is so low, assume that the reaction is irreversible.
  3. Why does assuming that the reaction is irreversible simplify the calculation in part (b)?

If the initial concentration of butadiene is 0.0200 M, what is the concentration remaining after 20.0 min?

In a transesterification reaction, a triglyceride reacts with an alcohol to form an ester and glycerol. Many students learn about the reaction between methanol (\({\bf{C}}{{\bf{H}}_{\bf{3}}}{\bf{OH}}\)) and ethyl acetate (\({\bf{C}}{{\bf{H}}_{\bf{3}}}{\bf{C}}{{\bf{H}}_{\bf{2}}}{\bf{OCOC}}{{\bf{H}}_{\bf{3}}}\)) as a sample reaction before studying the chemical reactions that produce biodiesel:

\({\bf{C}}{{\bf{H}}_{\bf{3}}}{\bf{OH + C}}{{\bf{H}}_{\bf{3}}}{\bf{C}}{{\bf{H}}_{\bf{2}}}{\bf{OCOC}}{{\bf{H}}_{\bf{3}}}{\bf{ - - - C}}{{\bf{H}}_{\bf{3}}}{\bf{OCOC}}{{\bf{H}}_{\bf{3}}}{\bf{ + C}}{{\bf{H}}_{\bf{3}}}{\bf{C}}{{\bf{H}}_{\bf{2}}}{\bf{OH}}\).The rate law for the reaction between methanol and ethyl acetate is, under certain conditions, determined to be: rate =\(k\left( {{\bf{C}}{{\bf{H}}_{\bf{3}}}{\bf{OH }}} \right)\). What is the order of reaction with respect to methanol and ethyl acetate, and what is the overall order of reaction?

From the following data, determine the rate law, the rate constant, and the order with respect to A for the reaction \({\bf{A}} \to {\bf{2C}}\).

Graph the following data to determine whether the reaction AโŸถB + C is first order.

Trial

Time(s)

(A)

1

4.0

0.220

2

8.0

0.144

3

12.0

0.110

4

16.0

0.088

5

20.0

0.074

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