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Atomic chlorine in the atmosphere reacts with ozone in the following pair of elementary reactions:

\({\bf{Cl + \;O3}}\left( {\bf{g}} \right){\bf{ - - - ClO}}\left( {\bf{g}} \right){\bf{ + \;O2}}\left( {\bf{g}} \right)\)(rate constant k1 )

\({\bf{ClO}}\left( {\bf{g}} \right){\bf{ + O - - - Cl}}\left( {\bf{g}} \right){\bf{ + \;O2}}\left( {\bf{g}} \right)\)(rate constant k2 )

Determine the overall reaction, write the rate law expression for each elementary reaction, identify any intermediates, and determine the overall rate law expression.

Short Answer

Expert verified

Overall reaction: \({{\bf{O}}_{\bf{3}}}\left( {\bf{g}} \right){\bf{ + O - - - - O2\;}}\left( {\bf{g}} \right)\)

\(\begin{aligned}{}{\bf{Rate1 = }}{{\bf{k}}_{\bf{1}}}{\bf{(}}{{\bf{O}}_{\bf{3}}}{\bf{)}}\left( {{\bf{Cl}}} \right){\bf{;}}\\{\bf{Rate2 = }}{{\bf{k}}_{\bf{2}}}\left( {{\bf{ClO}}} \right)\left( {\bf{O}} \right)\\{\bf{Intermediate: ClO}}\left( {\bf{g}} \right)\\{\bf{Overall rate = }}{{\bf{k}}_{\bf{2}}}{{\bf{k}}_{\bf{1}}}{\bf{(}}{{\bf{O}}_{\bf{3}}}\left) {\left( {{\bf{Cl}}} \right)} \right({\bf{O)}}{\bf{.}}\end{aligned}\)

Step by step solution

01

Rate of a Reaction

The rate of reaction may be defined as the speed of the reactant reacting to obtain a product in a particular reaction at a particular time. The concentration of the reactant and product are represented into mole/L.

02

Rate Law

The rate law or rate equation for a chemical reaction is an equation that links the initial or forward reaction rate with the concentrations or pressures of the reactants.

\({\bf{Rate = k}}{\left( {\bf{A}} \right)^{\bf{m}}}{\left( {\bf{B}} \right)^{\bf{n}}}\)

03

Explanation

\(\begin{aligned}{}{\bf{Cl + \;}}{{\bf{O}}_{\bf{3}}}\left( {\bf{g}} \right){\bf{ - - - ClO}}\left( {\bf{g}} \right){\bf{ + }}{{\bf{O}}_{\bf{2}}}{\bf{\;}}\left( {\bf{g}} \right){\bf{\;\;\;\;\;\;\;\;\;\;\;\;\;\;}}\\{\bf{ClO}}\left( {\bf{g}} \right){\bf{ + O - - - Cl}}\left( {\bf{g}} \right){\bf{ + \;}}{{\bf{O}}_{\bf{2}}}\left( {\bf{g}} \right)\end{aligned}\) \(\)

Overall Reaction:

\({{\bf{O}}_{\bf{3}}}\left( {\bf{g}} \right){\bf{ + O - - - - O2\;}}\left( {\bf{g}} \right)\) \(\)

\({\bf{Overall rate = }}{{\bf{k}}_{\bf{2}}}{{\bf{k}}_{\bf{1}}}{\bf{(}}{{\bf{O}}_{\bf{3}}}\left) {\left( {{\bf{Cl}}} \right)} \right({\bf{O)}}{\bf{.}}\)

Reaction 1:

\({\bf{Cl + \;O3}}\left( {\bf{g}} \right){\bf{ - - - ClO}}\left( {\bf{g}} \right){\bf{ + \;O2}}\left( {\bf{g}} \right)\)

\({\bf{Rate1 = }}{{\bf{k}}_{\bf{1}}}{\bf{(}}{{\bf{O}}_{\bf{3}}}{\bf{)}}\left( {{\bf{Cl}}} \right)\)

Reaction 2:

\({\bf{ClO}}\left( {\bf{g}} \right){\bf{ + O - - - Cl}}\left( {\bf{g}} \right){\bf{ + \;O2}}\left( {\bf{g}} \right)\)

\({\bf{Rate2 = }}{{\bf{k}}_{\bf{2}}}\left( {{\bf{ClO}}} \right)\left( {\bf{O}} \right)\)

The intermediate stable product of a chemical reaction that is then used as a starting material for another reaction.

\({\bf{Intermediate: ClO}}\left( {\bf{g}} \right)\)

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Most popular questions from this chapter

Account for the increase in reaction rate brought about by a catalyst.

Determine which of the two diagrams here (both for the same reaction) involves a catalyst, and identify the activation energy for the catalyzed reaction:

Some bacteria are resistant to the antibiotic penicillin because they produce penicillinase, an enzyme with a molecular weight of \({\bf{3 \times 1}}{{\bf{0}}^{\bf{4}}}\)g/mole that converts penicillin into inactive molecules. Although the kinetics of enzyme-catalysed reactions can be complex, at low concentrations this reaction can be described by a rate equation that is first order in the catalyst (penicillinase) and that also involves the concentration of penicillin. From the following data: 1.0 L of a solution containing 0.15 ยตg (\({\bf{0}}{\bf{.15 \times 1}}{{\bf{0}}^{{\bf{ - 6}}}}\)g) of penicillinase, determine the order of the reaction with respect to penicillin and the value of the rate constant.

(Penicillin) (M)

Rate (mole/L/min)

\({\bf{2}}{\bf{.0 \times 1}}{{\bf{0}}^{{\bf{ - 6}}}}\) \(\)

\({\bf{1}}{\bf{.0 \times 1}}{{\bf{0}}^{{\bf{ - 10}}}}\)

\({\bf{3}}{\bf{.0 \times 1}}{{\bf{0}}^{{\bf{ - 6}}}}\)

\({\bf{1}}{\bf{.5 \times 1}}{{\bf{0}}^{{\bf{ - 10}}}}\)

\({\bf{4}}{\bf{.0 \times 1}}{{\bf{0}}^{{\bf{ - 6}}}}\)

\({\bf{2}}{\bf{.0 \times 1}}{{\bf{0}}^{{\bf{ - 10}}}}\)

How much and in what direction will each of the following effect the rate of the reaction:

CO(g) + \({\bf{NO}}{}_{\bf{2}}\) (g)โŸถ \({\bf{CO}}{}_{\bf{2}}\) (g) + NO(g) if the rate law for the reaction is rate =\({\bf{k(NO}}{}_{\bf{2}}{{\bf{)}}^{\bf{2}}}{\bf{a}}\)?

  1. Decreasing the pressure of \({\bf{NO}}{}_{\bf{2}}\) from 0.50 atm to 0.250 atm.
  2. Increasing the concentration of CO from 0.01 M to 0.03 M.

Nitrosyl chloride, NOCl, decomposes to NO and \({\bf{C}}{{\bf{l}}_{\bf{2}}}\).

\({\bf{2NOCl(g)}} \to {\bf{2NO(g) + C}}{{\bf{l}}_{\bf{2}}}{\bf{(g)}}\)

Determine the rate law, the rate constant, and the overall order for this reaction from the following data:

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