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Question: Can the speed of a given molecule in a gas double at constant temperature? Explain your answer.

Short Answer

Expert verified

Yes, the speed of a given molecule in a gas doubles at constant temperature due to internal collisions.

Step by step solution

01

Concept Introduction

A molecule is a group of two or more atoms bound together by chemical bonds.

02

Speed of a Molecule

Yes, in a chamber that contains a sample of a gas, the speed of the gas molecules can double at time (or) reduce at any time, at constant temperature or without providing any other external energy.

This is possible due to the internal collisions between the gas molecules and with a container’s walls, which can lead either to increase the speed (or) to decrease the speed of the gas molecules.

Therefore, the speed of a given molecule in a gas doubles at constant temperature due to internal collisions.

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Most popular questions from this chapter

A sample of gas isolated from unrefined petroleum contains \({\rm{90}}{\rm{.0\% C}}{{\rm{H}}_{\rm{4}}}{\rm{, 8}}{\rm{.9\% }}{{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{6}}}{\rm{, and 1}}{\rm{.1\% }}{{\rm{C}}_{\rm{3}}}{{\rm{H}}_{\rm{8}}}\) at a total pressure of\({\rm{307}}{\rm{.2 kPa}}\). What is the partial pressure of each component of this gas? (The percentages given indicate the percent of the total pressure that is due to each component.)

Question: Under which of the following sets of conditions does a real gas behave most like an ideal gas, and for which conditions is a real gas expected to deviate from ideal behaviour? Explain.

(a) high pressure, small volume

(b) high temperature, low pressure

(c) low temperature, high pressure

A typical barometric pressure in Kansas City is 740 torr. What is this pressure in atmospheres, in millimeters of mercury, and in kilopascals?

Question: A 0.245L flask contains 0.467 mol \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) at 1590C. Calculate the pressure:

(a) using the ideal gas law

(b) using the van der Waals equation

(c) Explain the reason for the difference.

(d) Identify which correction (that for \({\rm{P}}\) or \({\rm{V}}\)) is dominant and why.

Question: During the discussion of gaseous diffusion for enriching uranium, it was claimed that \(^{{\rm{235}}}{{\rm{U}}_{\rm{6}}}\) diffuses 0.4% faster than\(^{{\rm{235}}}{{\rm{U}}_{\rm{6}}}\). Show the calculation that supports this value. The molar mass of \(^{{\rm{235}}}{{\rm{U}}_{\rm{6}}}{\rm{ = 235}}{\rm{.043930 + 6 \times 18}}{\rm{.998403 = 349}}{\rm{.034348 g/mol}}\), and the molar mass of \(^{{\rm{238}}}{{\rm{U}}_{\rm{6}}}{\rm{ = 238}}{\rm{.050788 + 6 \times 18}}{\rm{.998403 = 352}}{\rm{.041206 g/mol}}\).

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