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A typical barometric pressure in Kansas City is 740 torr. What is this pressure in atmospheres, in millimeters of mercury, and in kilopascals?

Short Answer

Expert verified
  1. 740Torr = 0.9736 atm
  2. 740Torr = 740 mm of Hg
  3. 740Torr = 98.65 KPa

Step by step solution

01

Define pressure

Force applied perpendicular to an object's surface per unit area across which that force is spread is known as pressure.

02

Explanation

a) Converting Torr pressure to atm.

1 Torr = 0.001315 atm.

740 Torr = (740) x (0.001315) atm.

=0.9736 atm

Therefore, 740 Torr of Hg is equal to 0.9736 atm.

b) Converting Torr pressure to atm.

1 Torr = 1mm of Hg

740 Torr = (740) x (1) mm of Hg.

=740 mm of Hg

Therefore, 740 Torr is equal to 740mm of Hg.

c) Converting torr to kPa pressure.

1 Torr = 0.1333 Kpa.

740 Torr = (615) x (0.1333) Kpa.

= 98.65 Kpa.

Therefore, 740 Torr is equal to 98.65 Kpa.

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