Question

What is the approximate value of the equilibrium constant K_P for the change C₂H₅OC₂H₅ (l)⇌C₂ H₅OC₂H₅ (g) at 25 °C.

(Vapor pressure was described in the previous chapter on liquids and solids; refer back to this chapter to find the relevant information needed to solve this problem.)

Short answer

\({K_p} = 0.7\;{\rm{atm}}{\rm{.}}\)

Step-by-step solution

Vapor pressure of Diethyl ether:

The reaction given

The pressure of a diethyl ether vapor at 25^oc is \(0.7\;{\rm{atm}}{\rm{.}}\)

The approximate value of the equilibrium constant KP:

Let us calculate the equilibrium constant \({{\rm{K}}_{\rm{p}}}\) for the change at 25^oc

The equilibrium constant\({{\rm{K}}_{\rm{p}}}:\)

\(\begin{array}{l}{K_p} = \frac{{{P_{{C_2}{H_5}O{C_2}{H_5}(g)}}}}{1}\\\;\;\;\;\; = {P_{{C_2}{H_5}O{C_2}{H_5}(g)}}\\\;\;\;\;\; = 0.7\;{\rm{atm}}{\rm{.}}\end{array}\)