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For which of the reactions in Exercise 13.15 does\({K_c}\)(calculated using concentrations) equal\({K_p}\)(calculated using pressures)?

(a) \(C{H_4}(g) + C{l_2} \rightleftharpoons C{H_3}CI(g) + HCI(g)\)

(b) \({N_2}(g) + {O_2}(g)\rightleftharpoons 2NO(g)\)

(c) \(2S{O_2}(\;g) + {O_2}(\;g)\rightleftharpoons 2S{O_3}(\;g)\)

(d) \(BaS{O_3}(s)\rightleftharpoons BaO(s) + S{O_2}(g)\)

(e) \({P_4}(g) + 5{O_2}(g)\rightleftharpoons{P_4}{O_{10}}(s)\)

(f) \(B{r_2}(\;g)\rightleftharpoons 2Br(g)\)

(g) \(C{H_4}(g) + 2{O_2}(g)\rightleftharpoons C{O_2}(g) + 2{H_2}O(l)\)

(h)\(CuS{O_4} \times 5{H_2}O(s)\rightleftharpoons CuS{O_4}(s) + 5{H_2}O(g)\)

Short Answer

Expert verified
  1. The values are equal \({{\rm{K}}_{\rm{p}}} = {{\rm{K}}_{\rm{c}}}\).
  2. The values are equal \({{\rm{K}}_{\rm{p}}} = {{\rm{K}}_{\rm{c}}}\)
  3. The values are not equal \({{\rm{K}}_{\rm{p}}} \ne {{\rm{K}}_{\rm{c}}}\)
  4. The values are not \({{\rm{K}}_{\rm{p}}} \ne {{\rm{K}}_{\rm{c}}}\)
  5. The values are not equal \({{\rm{K}}_{\rm{p}}} \ne {{\rm{K}}_{\rm{c}}}\)
  6. The values are not equal \({{\rm{K}}_{\rm{p}}} \ne {{\rm{K}}_{\rm{c}}}\)
  7. The values are not equal \({{\rm{K}}_{\rm{p}}} \ne {{\rm{K}}_{\rm{c}}}\)
  8. The values are not equal \({{\rm{K}}_{\rm{p}}} \ne {{\rm{K}}_{\rm{c}}}\)

Step by step solution

01

Definition of equilibrium constant 

The forward and backward (reverse) processes have identical rates in the equilibrium mixture.

For a chemical reaction is

\(A \to B + C\)

The equilibrium constant will be expressed as:

\({K_C} = \frac{{({\rm{B}})({\rm{C}})}}{{({\rm{A}})}}\)

Where,\((A),\;(B)\)and\((C)\)are equilibrium concentration of A, B and C respectively.

When there are an equal number of gas components on both sides of the reaction arrow, the value of\({K_c}\)equals the value of\({K_p}.\)

Both are related to each other as follows:

\({{\rm{K}}_{\rm{p}}} = {{\rm{K}}_{\rm{c}}}{({\rm{RT}})^{\Delta {\rm{n}}}}\)

02

Check\({K_c}\)and \({K_p}\)are equal or not for part (a)

a.\({\rm{C}}{{\rm{H}}_4}(\;{\rm{g}}) + {\rm{C}}{{\rm{l}}_2}(\;{\rm{g}})\rightleftharpoons{\rm{C}}{{\rm{H}}_3}{\rm{Cl}}({\rm{g}}) + {\rm{HCl}}({\rm{g}})\)

So, both sides contain equal number of gaseous components which is two. Therefore, \({{\rm{K}}_{\rm{p}}}\)and \({{\rm{K}}_{\rm{c}}}\) are equal.

\({{\rm{K}}_{\rm{p}}} = {{\rm{K}}_{\rm{c}}}{({\rm{RT}})^{\Delta {\rm{n}}}}\)

03

Check \({K_c}\)and \({K_p}\)are equal or notfor part (b)

b.\({N_2}(g) + {O_2}(g)\rightleftharpoons 2NO(g)\)

So, both sides contain equal number of gaseous components. Therefore, \({{\rm{K}}_{\rm{p}}}\)and \({{\rm{K}}_{\rm{c}}}\) are equal.

04

Check \({K_c}\)and \({K_p}\)are equal or notfor part (c)

c. \(2{\rm{S}}{{\rm{O}}_2}(\;{\rm{g}}) + {{\rm{O}}_2}(\;{\rm{g}}) \to 2{\rm{S}}{{\rm{O}}_3}(\;{\rm{g}})\)

\(2{\rm{S}}{{\rm{O}}_2}(\;{\rm{g}}) + {{\rm{O}}_2}(\;{\rm{g}}) \to 2{\rm{S}}{{\rm{O}}_3}(\;{\rm{g}})\)

So, both sides does not contain equal number of gaseous components. Therefore, \({{\rm{K}}_{\rm{p}}}\)and \({{\rm{K}}_{\rm{c}}}\) are not equal.

05

Check \({K_c}\)and \({K_p}\) are equal or notfor part (d)

d. \({\rm{BaS}}{{\rm{O}}_3}(\;{\rm{s}})\rightleftharpoons {\rm{BaO}}({\rm{S}}) + {\rm{S}}{{\rm{O}}_2}(\;{\rm{g}})\)

So, both sides does not contain equal number of gaseous components. Therefore, \({{\rm{K}}_{\rm{p}}}\)and \({{\rm{K}}_{\rm{c}}}\) are not equal.

06

Check \({K_c}\)and \({K_p}\) are equal or notfor part (e)

e. \({{\rm{P}}_4}(\;{\rm{g}}) + 5{{\rm{O}}_2}(\;{\rm{g}})\rightleftharpoons {{\rm{P}}_4}{{\rm{O}}_{10}}(\;{\rm{S}})\)

So, both sides does not contain equal number of gaseous components. Therefore, \({{\rm{K}}_{\rm{p}}}\)and \({{\rm{K}}_{\rm{c}}}\) are not equal..

07

Check \({K_c}\) and \({K_p}\) are equal or notfor part (f)

f. \({\rm{B}}{{\rm{r}}_2}(\;{\rm{g}})\rightleftharpoons 2{\rm{Br}}({\rm{g}})\)

So, both sides does not contain equal number of gaseous components.

Therefore, \({{\rm{K}}_{\rm{p}}}\)and \({{\rm{K}}_{\rm{c}}}\) are not equal.

08

Check \({K_c}\) and \({K_p}\) are equal or not for part (g)

g. \({\rm{C}}{{\rm{H}}_4}(\;{\rm{g}}) + 2{{\rm{O}}_2}(\;{\rm{g}})\rightleftharpoons {\rm{C}}{{\rm{O}}_2}(\;{\rm{g}}) + {{\rm{H}}_2}{\rm{O}}({\rm{l}})\)

So, both sides does not contain equal number of gaseous components.

Therefore, \({{\rm{K}}_{\rm{p}}}\)and \({{\rm{K}}_{\rm{c}}}\) are not equal.

09

Check \({K_c}\) and \({K_p}\) are equal or not for part (h)

h. \({\rm{CuS}}{{\rm{O}}_4}.5{{\rm{H}}_2}{\rm{O}}({\rm{s}})\rightleftharpoons {\rm{CuS}}{{\rm{O}}_4}(\;{\rm{s}}) + 5{{\rm{H}}_2}{\rm{O}}({\rm{l}})\)

So, both sides does not contain equal number of gaseous components.

Therefore, \({{\rm{K}}_{\rm{p}}}\)and \({{\rm{K}}_{\rm{c}}}\) are not equal.

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Most popular questions from this chapter

Question: Consider the equilibrium

4NO2(g) + 6H2 O(g) ⇌ 4NH3(g) + 7O2(g)

(a) What is the expression for the equilibrium constant (Kc) of the reaction?

(b) How must the concentration of NH3 change to reach equilibrium if the reaction quotient is less than the equilibrium constant?

(c) If the reaction were at equilibrium, how would a decrease in pressure (from an increase in the volume of the reaction vessel) affect the pressure of NO2?

(d) If the change in the pressure of NO2 is 28 torr as a mixture of the four gases reaches equilibrium, how much will the pressure of O2 change?

A student solved the following problem and found \(\left[ {{N_2}{O_4}} \right] = 0.16M\)at equilibrium. How could this student recognize that the answer was wrong without reworking the problem? The problem was: What is the equilibrium concentration of \(\left[ {{N_2}{O_4}} \right]\) in a mixture formed from a sample of \(N{O_2}\) with a concentration of \(0.10M\)?

\(2N{O_2}(g) \rightleftharpoons {N_2}{O_4}(g)\)

\({K_c} = 160\)

For which of the reactions in Exercise 13.16 does \({K_c}\) (calculated using concentrations) equal \({K_p}\)(calculated using pressures)?

(a) \({N_2}(g) + 3{H_2}(g)\rightleftharpoons 2N{H_3}(g)\)

(b) \(4N{H_3}(g) + 5{O_2}(g)\rightleftharpoons 4NO(g) + 6{H_2}O(g)\)

(c) \({N_2}{O_4}(g)\rightleftharpoons 2N{O_2}(g)\)

(d) \(C{O_2}(g) + {H_2}(g)\rightleftharpoons CO(g) + {H_2}O(g)\)

(e) \(N{H_4}Cl(s)\rightleftharpoons N{H_3}(g) + HCl(g)\)

(f) \(2\;Pb{\left( {N{O_3}} \right)_2}(s)\rightleftharpoons 2PbO(s) + 4N{O_2}(g) + {O_2}(g)\)

(g) \(2{H_2}(g) + {O_2}(g)\rightleftharpoons 2{H_2}O(l)\)

(h) \({S_8}(g)\rightleftharpoons 8\;S(g)\)

Question:Calculate the value of the equilibrium constant \({K_P}\) for the reaction \(2NO(g) + C{l_2}(g) \rightleftharpoons 2NOCl(g)\) from these equilibrium pressures: NO, \(0.050atm;C{l_2},0.30atm;NOCl,1.2atm\)

Question: Calculate the pressures of NO, Cl2, and NOCl in an equilibrium mixture produced by the reaction of a starting mixture with 4.0 atm NO and 2.0 atm Cl2. (Hint: KP is small; assume the reverse reaction goes to completion then comes back to equilibrium.)

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