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Write the mathematical expression for the reaction quotient, \({Q_c}\), for each of the following reactions:

(a) \({N_2}(g) + 3{H_2}(g) \rightleftharpoons 2N{H_3}(g)\)

(b) \(4N{H_3}(g) + 5{O_2}(g) \rightleftharpoons 4NO(g) + 6{H_2}O(g)\)

(c) \({N_2}{O_4}(g) \rightleftharpoons 2N{O_2}(g)\)

(d) \(C{O_2}(g) + {H_2}(g) \rightleftharpoons CO(g) + {H_2}O(g)\)

(e) \(N{H_4}Cl(s) \rightleftharpoons N{H_3}(g) + HCl(g)\)

(f) \(2\;Pb{\left( {N{O_3}} \right)_2}(s) \rightleftharpoons 2PbO(s) + 4N{O_2}(g) + {O_2}(g)\)

(g) \(2{H_2}(g) + {O_2}(g) \rightleftharpoons 2{H_2}O(l)\)

(h) \({S_8}(g) \rightleftharpoons 8\;S(g)\)

Short Answer

Expert verified
  1. The required reaction quotient is \({Q_c} = \frac{{{{\left| {N{H_3}} \right|}^2}}}{{\left( {{{\left. {\;{N_2}||{H_2}} \right|}^3}} \right.}}\)
  2. The required reaction quotient is \({Q_c} = \frac{{\left| {N{O^4}} \right|{H_2}O{O^6}}}{{{{\left| {N{H_3}} \right|}^4}{{\left| {{O_2}} \right|}^3}}}\)
  3. The required reaction quotient is \({Q_c} = \frac{{\left| {{N_2}{O_4}} \right|}}{{{{\left| {N{O_,}} \right|}^2}}}\)
  4. The required reaction quotient is \({Q_c} = \frac{{\left| {C{O^{\\mid {H_2}O}}} \right|}}{{\left| {C{O_2}} \right|\left| {{H_2}} \right|}}\)
  5. The required reaction quotient is \({Q_c} = \left( {N{H_3}} \right)(HCl)\)
  6. The required reaction quotient is \({Q_c} = {\left( {N{O_2}} \right)^4}\left( {{O_2}} \right)\)
  7. The required reaction quotient is \({Q_c} = \frac{1}{{{{\left| {{H_2}} \right|}^2}\left| {{O_2}} \right|}}\)
  8. The required reaction quotient is \({Q_c} = \frac{{|S{|^8}}}{{\left| {{S_8}} \right|}}\)

Step by step solution

01

Definition of reaction quotient

  • Under non-equilibrium conditions, the reaction quotient 'Q' is defined as the ratio of the product of initial product concentrations to the product of initial reactant concentrations.
02

Determine the reaction quotient \({Q_c}\) for  \({N_2}(g) + 3{H_2}(g)  \rightleftharpoons  2N{H_3}(g)\)

(a)

In the case of any reversible response,\({Q_c}\), is the product of all the reactants' concentrations increased to the power of their individual reaction coefficients.

For the form's reversible reaction, \(aA + bB \rightleftharpoons cC + dD\)

\({Q_c} = \frac{{\mid C{)^q}|D{|^d}}}{{|A{|^\mid }|B{|^b}}}\)

So the reaction, \({N_2}(\;g) + 3{H_2}(\;g) \rightleftharpoons 2N{H_3}(\;g)\)

The required reaction quotient is

\({Q_c} = \frac{{{{\left| {N{H_3}} \right|}^2}}}{{|\;N|{{\left| {{H_3}} \right|}^3}}}\)

03

Determine the reaction quotient \({Q_c}\) for \(4N{H_3}(g) + 5{O_2}(g)  \rightleftharpoons 4NO(g) + 6{H_2}O(g)\)

(b)

In the case of any reversible response,\({Q_c}\), is the product of all the reactants' concentrations increased to the power of their individual reaction coefficients.

For the form's reversible reaction,\(aA + bB \rightleftharpoons cC + dD\)

\({Q_c} = \frac{{\mid C{)^c}|D{|^d}}}{{|A{|^\mid }|B{|^b}}}\)

So, the reaction \(4N{H_3}(\;g) + 5{O_2}(\;g)\rightleftharpoons 4NO(g) + 6{H_2}O(g)\)

The required reaction quotient is \({Q_c} = \frac{{\left| {N{O^4}} \right|{H_2}O{O^6}}}{{{{\left| {N{H_3}} \right|}^4}{{\left| {{O_2}} \right|}^3}}}\)

04

Determine the reaction quotient \({Q_c}\) for \({N_2}{O_4}(g) \rightleftharpoons 2N{O_2}(g)\)

(c)

In the case of any reversible response,\({Q_c}\), is the product of all the reactants' concentrations increased to the power of their individual reaction coefficients.

For the form's reversible reaction, \(aA + bB \rightleftharpoons cC + dD\)

\({Q_c} = \frac{{\mid C{)^c}|D{|^d}}}{{|A{|^\mid }|B{|^b}}}\)

So, the reaction, \({N_2}{O_4}(\;g) \rightleftharpoons 2N{O_2}(\;g)\)

The required reaction quotient is \({Q_c} = \frac{{\left| {{N_2}{O_4}} \right|}}{{{{\left| {N{O_,}} \right|}^2}}}\)

05

Determine the reaction quotient \({Q_c}\)for \(C{O_2}(g) + {H_2}(g)\rightleftharpoons  CO(g) + {H_2}O(g)\) 

(d) In the case of any reversible response, \({Q_c}\), is the product of all the reactants' concentrations increased to the power of their individual reaction coefficients.

For the form's reversible reaction, \(aA + bB \rightleftharpoons cC + dD\)

\({Q_c} = \frac{{\mid C{)^c}|D{|^d}}}{{|A{|^{a\mid }}|B{|^b}}}\)

So, the reaction, \(C{O_2}(\;g) + {H_2}(\;g) \rightleftharpoons CO(g) + {H_2}O(g)\)

The required reaction quotient is \({Q_c} = \frac{{\left| {C{O^{\mid {H_2}O}}} \right|}}{{\left| {C{O_2}} \right|\left| {{H_2}} \right|}}\)

06

Determine the reaction quotient \({Q_c}\) for \(N{H_4}Cl(s) \rightleftharpoons N{H_3}(g) + HCl(g)\) 

(e)

In the case of any reversible response,\({Q_c}\), is the product of all the reactants' concentrations increased to the power of their individual reaction coefficients.

For the form's reversible reaction, \(aA + bB \rightleftharpoons cC + dD\)

\({Q_c} = \frac{{\mid C{)^c}|D{|^d}}}{{|A{|^{a\mid }}|B{|^b}}}\)

Furthermore, because the concentration of pure solids and liquids does not fluctuate considerably during the course of a reversible reaction, the concentration term for them is not included in the reaction quotient.

So, the reaction, \(N{H_4}Cl(s) \rightleftharpoons N{H_3}(\;g) + HCl(g)\)

The required reaction quotient is \({Q_c} = \left( {N{H_3}} \right)(HCl)\)

07

Determine the reaction quotient \({Q_c}\)for \(2\;Pb{\left( {N{O_3}} \right)_2}(s) \rightleftharpoons 2PbO(s) + 4N{O_2}(g) + {O_2}(g)\)

(f)

In the case of any reversible response,\({Q_c}\), is the product of all the reactants' concentrations increased to the power of their individual reaction coefficients.

For the form's reversible reaction, \(aA + bB \rightleftharpoons cC + dD\)

\({Q_c} = \frac{{\mid C{)^c}|D{|^d}}}{{|A{|^{a\mid }}|B{|^b}}}\)

Furthermore, because the concentration of pure solids and liquids does not change much during a reversible reaction, the concentration term for them is not included in the reaction quotient.

So, the reaction, \(2\;Pb{\left( {N{O_3}} \right)_2}(\;s) \rightleftharpoons 2PbO(s) + 4N{O_2}(\;g) + {O_2}(\;g)\)

The required reaction quotient is \({Q_c} = {\left( {N{O_2}} \right)^4}\left( {{O_2}} \right)\)

08

Determine the reaction quotient \({Q_c}\) for \(2{H_2}(g) + {O_2}(g) \rightleftharpoons 2{H_2}O(l)\)

(g) In the case of any reversible response, \({Q_c}\), is the product of all the reactants' concentrations increased to the power of their individual reaction coefficients.

For the form's reversible reaction, \(aA + bB \rightleftharpoons cC + dD\)

\({Q_c} = \frac{{\mid C{)^c}|D{|^d}}}{{|A{|^{a\mid }}|B{|^b}}}\)

So, the reaction \(2{H_2}(\;g) + {O_2}(\;g) \rightleftharpoons 2{H_2}O(l)\)

Furthermore, because the concentration of pure solids and liquids does not change much during a reversible reaction, the concentration term for them is not included in the reaction quotient.

The required reaction quotient is \({Q_c} = \frac{1}{{{{\left| {{H_2}} \right|}^2}\left| {{O_2}} \right|}}\)

09

Determine the reaction quotient \({Q_c}\) for \({S_8}(g) \rightleftharpoons  8\;S(g)\)

(h)

In the case of any reversible response,\({Q_c}\), is the product of all the reactants' concentrations increased to the power of their individual reaction coefficients.

For the form's reversible reaction, \(aA + bB \rightleftharpoons cC + dD\)

\({Q_c} = \frac{{\mid C{)^c}|D{|^d}}}{{|A{|^{a\mid }}|B{|^b}}}\)

So, the reaction, \({S_8}(g) \rightleftharpoons 8\;S(g)\)

The required reaction quotient is \({Q_c} = \frac{{|S{|^8}}}{{\left| {{S_8}} \right|}}\)

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Most popular questions from this chapter

Question: \(\;A\;0.72 - mol\)sample of \(PC{l_5}\)is put into a \(1.00 - L\) vessel and heated. At equilibrium, the vessel contains \(0.40mol\) of \(PC{l_3}(g)\) and \(0.40mol\;of\;C{l_2}(g)\). Calculate the value of the equilibrium constant for the decomposition of \(PC{l_5}\;to\;\)\(PC{l_3}\;and\;C{l_2}\)at this temperature.

Question: At 25 ยฐC and at 1 atm, the partial pressures in an equilibrium mixture of N2O4 and NO2 are PN2O4= 0.70 atm and PNO2 = 0.30 atm.

(a) Predict how the pressures of NO2 and N2O4 will change if the total pressure increases to 9.0 atm. Will they increase, decrease, or remain the same?

(b) Calculate the partial pressures of NO2 and N2O4 when they are at equilibrium at 9.0 atm and 25 ยฐC

For which of the reactions in Exercise 13.15 does\({K_c}\)(calculated using concentrations) equal\({K_p}\)(calculated using pressures)?

(a) \(C{H_4}(g) + C{l_2} \rightleftharpoons C{H_3}CI(g) + HCI(g)\)

(b) \({N_2}(g) + {O_2}(g)\rightleftharpoons 2NO(g)\)

(c) \(2S{O_2}(\;g) + {O_2}(\;g)\rightleftharpoons 2S{O_3}(\;g)\)

(d) \(BaS{O_3}(s)\rightleftharpoons BaO(s) + S{O_2}(g)\)

(e) \({P_4}(g) + 5{O_2}(g)\rightleftharpoons{P_4}{O_{10}}(s)\)

(f) \(B{r_2}(\;g)\rightleftharpoons 2Br(g)\)

(g) \(C{H_4}(g) + 2{O_2}(g)\rightleftharpoons C{O_2}(g) + 2{H_2}O(l)\)

(h)\(CuS{O_4} \times 5{H_2}O(s)\rightleftharpoons CuS{O_4}(s) + 5{H_2}O(g)\)

Question: An equilibrium is established according to the following equation

\({K_c} = 4.6\)

What will happen in a solution that is 0.20 M in each \({\rm{Hg}}_2^{2 + },{\rm{NO}}_3^ - ,{{\rm{H}}^ + },{\rm{H}}{{\rm{g}}^{2 + }}\)and \({\rm{HN}}{{\rm{O}}_2}{\rm{\;?\;}}\)

a)\({\rm{H}}{{\rm{g}}_2}^{2 + }\) will be oxidized and \({\rm{N}}{{\rm{O}}_3}\)reduced,

b) \({\rm{H}}{{\rm{g}}_2}^{2 + }\)will be oxidized and \({\rm{N}}{{\rm{O}}_3}\) oxidized.

c)\({\rm{H}}{{\rm{g}}_2}^{2 + }\)will be oxidized and \({\rm{HN}}{{\rm{O}}_2}\)reduced.

d) \({\rm{H}}{{\rm{g}}_2}^{2 + }\)will be oxidized and \({\rm{HN}}{{\rm{O}}_2}\)oxidized.

(e) There will be no change because all reactants and products have an activity of 1.

Calculate the equilibrium concentrations of NO, O2, and NO2 in a mixture at 250 ยฐC that results from the reaction of 0.20 M NO and 0.10 M O2. (Hint: K is large; assume the reaction goes to completion then comes back to equilibrium.)

\(2NO(g) + {O_2}(g) \rightleftharpoons 2N{O_2}(g)\quad {K_c} = 2.3 \times 1{0^5}\;at\;25{0^o}C\)

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