Question

The weather in Europe was unusually warm during the summer of \(1995\). The TV news reported temperatures as high as \(45{\rm{ }}^\circ C\). What was the temperature on the Fahrenheit scale?

Short answer

The temperature on the Fahrenheit scale is \({113^ \circ }F\).

Step-by-step solution

Write the equations for converting between Celsius and Fahrenheit.

The equation for converting Celsius into Fahrenheit temperature is:

\({T_{{}^ \circ F}} = \frac{9}{5} \times {T_{{}^ \circ C}} + 32\)

The equation for converting Fahrenheit into Celsius temperature is:

\({T_{{}^ \circ C}} = \frac{5}{9} \times {T_{{}^ \circ F}} - 32\)

Determine the temperature in Fahrenheit.

It is given that the temperature of scalding water is\(45^\circ C\).

\(\begin{aligned}{}{T_{{}^ \circ F}}& = \frac{9}{5} \times 45{\rm{ }}^\circ C + 32\\{\rm{ }} &= {113^ \circ }F\end{aligned}\)

Hence the temperature \( = {113^ \circ }F\).