Question

Suppose you are presented with a clear solution of sodium thiosulfate, \({\bf{N}}{{\bf{a}}_{\bf{2}}}{{\bf{S}}_{\bf{2}}}{{\bf{O}}_{\bf{3}}}\). How could you determine whether the solution is unsaturated, saturated, or supersaturated?

Short answer

By adding, more solute in the solvent we can find out the nature of solution. \(\)

Step-by-step solution

Saturated and Unsaturated solution

A saturated solution is a solution with a solute that dissolves until it’s far now no longer capable of dissolving anymore, leaving the undissolved substances at the bottom.

An unsaturated solution is a solution with an entire lot of great deal much less solute than the saturated solution that actually dissolves, leaving no substances at the bottom.

Supersaturated is a solution that consists of extra undissolved solute than the saturated answer due to its tendency to crystalize and precipitate.

Explanation

To determine the nature of the solution we can add more solute to the solvent if the solute does not dissolve then it is a saturated solution and if there is undissolved solute leftover then it is a supersaturated solution.

But if the solute is dissolved in the solvent, then it is an unsaturated solution.