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Even though Ca(OH)2 is an inexpensive base, its limited solubility restricts its use. What is theof a saturated solution of Ca(OH)2?

Short Answer

Expert verified

The pH of the solution is 12.14

Step by step solution

01

Define saturated solution

This state is when the solution has reached a point in which no more solute can be added. The addition of solute after this point would result in a solid precipitate or gas being released. Such a mixture is called a saturated solution

02

The reaction of the saturated solution

Reaction of

Ca(OH)2(s) ⇌ Ca2+ (aq) +2OH- (aq)

Reaction of

Kspof Ca(OH)2is Ksp = [Ca2+] . [OH-] = 1.3.10-6

The molar solubility of Ca2+ is ‘s’

The molar solubility of OH-is ‘2s’

03

  Step 3: The pH-saturated solution Ca(OH)2

Let us find the value of

\begin{aligned}{{K_{sp}}=\left[{C{a^{2+}}}\right]\cdot{{\left[{O{H^-}}\right]}^2}}\\{1.3\cdot{{10}^{-6}}=s\cdot{{(2s)}^2}}\\{4{s^3}=1.3\cdot{{10}^{-6}}}\\{s=6.875\cdot{{10}^{-3}}}\\{\left[{O{H^-}}\right]=2s=1.375\cdot{{10}^{-2}}{\rm{M}}}\end{aligned}

04

Finding the pH

Let us calculate

\begin{aligned}{pOH=-\log\left[{O{H^-}}\right]}\\{=-\log\left[{1.375\cdot{{10}^{-2}}}\right]}\\{=1.86}\end{aligned}

pH Of the saturated solution

\begin{aligned}{pH=14-pOH}\\{=14-1.86}\\{=12.14}\end{aligned}

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Most popular questions from this chapter

A \({\bf{0}}.{\bf{125}}{\rm{ }}{\bf{M}}\) solution of \({\bf{Mn}}{\left( {{\bf{N}}{{\bf{O}}_{\bf{3}}}} \right)_{\bf{2}}}\) is saturated with\({{\bf{H}}_{\bf{2}}}{\bf{S}}{\rm{ }}\left( {\left[ {{{\bf{H}}_{\bf{2}}}{\bf{S}}} \right]{\rm{ }} = {\rm{ }}{\bf{0}}.{\bf{10}}{\rm{ }}{\bf{M}}} \right)\). At what pH does MnS begin to precipitate?

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