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Question:Cobalt–60 and iodine–131 are radioactive isotopes commonly used in nuclear medicine. How many protons,neutrons, and electrons are in atoms of these isotopes? Write the complete electron configuration for each isotope.

Short Answer

Expert verified

Cobalt - 60

Iodine – 131

Protons

27

53

Electrons

27

53

Neutrons

33

78

Electron configuration

1s22s22p63s23p64s23d7

1s22s22p63s23p64s23d104p65s24d105p5

Step by step solution

01

Determine protons, neutrons, and electrons in these isotopes.  

Isotopes have a different number of neutrons but are the same elements, and have the same number of electrons and protons. Hence, observing the periodic table,

Cobalt - 60

Iodine – 131

Protons

27

53

Electrons

27

53

Neutrons

33

78

02

Write the complete electron configuration for each isotope.  

From the periodic table, we can write the electron configuration as,

Cobalt-60 = 1s22s22p63s23p64s23d7

Iodine-131 = 1s22s22p63s23p64s23d104p65s24d105p5

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