Q53 E Consider this question: What is ... [FREE SOLUTION]

Chapter 3: Q53 E (page 171)

_{Consider this question: What is the molarity of KMnO4 in a solution of 0.0908g of KMnO4 in 0.500L of solution?}

_{Outline the steps necessary to answer the question}
_{Answer the question.}

Short Answer

Expert verified

_{Molarity is defined as the number of moles of a compound dissolved in an amount of solvent. It is also known as molar concentration and has a unit mol/L or molar(M)}

Step by step solution

Step 1: Given

Given the mass of KMnO4= 0.0908g

Given volume of solution= 0.500L

The formula we shall use to determine molarity is :

(a) Molarity of a solution = number of moles/volume of solution in L

Again, number of moles = (given mass )/(molar mass )

= 0.0908g/(158.04g/mol)

= 0.000575 mol

Therefore, by substituting the values, we get

Molarity = 0.000575mol/0.500L

=1.15×10^-3 M

(b) The molarity of KMnO4 containing 0.0908g of KMnO4 in 0.500L of solution is 1.15×10^-3 M

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_{Consider this question: What is the molarity of KMnO4 in a solution of 0.0908g of KMnO4 in 0.500L of solution?}

_{Outline the steps necessary to answer the question}

_{Answer the question.}

Short Answer

_{Molarity is defined as the number of moles of a compound dissolved in an amount of solvent. It is also known as molar concentration and has a unit mol/L or molar(M)}

Step by step solution

Step 1: Given

Given the mass of KMnO4= 0.0908g

Given volume of solution= 0.500L

The formula we shall use to determine molarity is :

(a) Molarity of a solution = number of moles/volume of solution in L

Again, number of moles = (given mass )/(molar mass )

= 0.0908g/(158.04g/mol)

= 0.000575 mol

Therefore, by substituting the values, we get

Molarity = 0.000575mol/0.500L

=1.15×10^-3 M

(b) The molarity of KMnO4 containing 0.0908g of KMnO4 in 0.500L of solution is 1.15×10^-3 M

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Most popular questions from this chapter

A cough syrup contains 5.0% ethyl alcohol C₂H₅OH, by mass. If the density of the solution is 0.9928 g/ml determine the molarity of alcohol in the cough syrup.

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Consider this question: What is the molarity of KMnO4 in a solution of 0.0908g of KMnO4 in 0.500L of solution?

Outline the steps necessary to answer the question

Answer the question.

Short Answer

Molarity is defined as the number of moles of a compound dissolved in an amount of solvent. It is also known as molar concentration and has a unit mol/L or molar(M)

Step by step solution

Step 1: Given

Given the mass of KMnO4= 0.0908g

Given volume of solution= 0.500L

The formula we shall use to determine molarity is :

(a) Molarity of a solution = number of moles/volume of solution in L

Again, number of moles = (given mass )/(molar mass )

= 0.0908g/(158.04g/mol)

= 0.000575 mol

Therefore, by substituting the values, we get

Molarity = 0.000575mol/0.500L

=1.15×10-3 M

(b) The molarity of KMnO4 containing 0.0908g of KMnO4 in 0.500L of solution is 1.15×10-3 M

One App. One Place for Learning.

Most popular questions from this chapter

A cough syrup contains 5.0% ethyl alcohol C2H5OH, by mass. If the density of the solution is 0.9928 g/ml determine the molarity of alcohol in the cough syrup.

Recommended explanations on Chemistry Textbooks

Kinetics

Chemical Analysis

Chemistry Branches

Making Measurements

Physical Chemistry

Inorganic Chemistry

Study anywhere. Anytime. Across all devices.

_{Consider this question: What is the molarity of KMnO4 in a solution of 0.0908g of KMnO4 in 0.500L of solution?}

_{Outline the steps necessary to answer the question}

_{Answer the question.}

_{Molarity is defined as the number of moles of a compound dissolved in an amount of solvent. It is also known as molar concentration and has a unit mol/L or molar(M)}

=1.15×10^-3 M

(b) The molarity of KMnO4 containing 0.0908g of KMnO4 in 0.500L of solution is 1.15×10^-3 M

A cough syrup contains 5.0% ethyl alcohol C₂H₅OH, by mass. If the density of the solution is 0.9928 g/ml determine the molarity of alcohol in the cough syrup.