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Chapter 3: Q53 E (page 171)

Consider this question: What is the molarity of KMnO4 in a solution of 0.0908g of KMnO4 in 0.500L of solution?

  1. Outline the steps necessary to answer the question

  2. Answer the question.

Short Answer

Expert verified

Molarity is defined as the number of moles of a compound dissolved in an amount of solvent. It is also known as molar concentration and has a unit mol/L or molar(M)

Step by step solution

01

Step 1: Given

Given the mass of KMnO4= 0.0908g

Given volume of solution= 0.500L

02

The formula we shall use to determine molarity is :

(a) Molarity of a solution = number of moles/volume of solution in L

Again, number of moles = (given mass )/(molar mass )

= 0.0908g/(158.04g/mol)

= 0.000575 mol

Therefore, by substituting the values, we get

Molarity = 0.000575mol/0.500L

=1.15×10-3 M

(b) The molarity of KMnO4 containing 0.0908g of KMnO4 in 0.500L of solution is 1.15×10-3 M

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Most popular questions from this chapter

Determine the number of moles of compound and the number of moles of each type of atom in each of the following:

(a) 25.0 g of propylene, C3H6

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(e) 325 mg of aspirin, C6H4(CO2H) (CO2CH3)

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Question: Consider this question: What is the molarity of HCl if 35.23ml of a solution of HCl contain 0.3366g of HCl?

(a) Outline the steps necessary to answer the question.

(b) Answer the question.

Calculate the molar mass of each of the following compounds:

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(b) ammonia, NH3

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(e) boric acid, B(OH)3

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