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How many C4H10 molecules are contained in 9.213 g of this compound? How many hydrogen atoms?

Short Answer

Expert verified

No of molecules of C4H10 will be \(9.452 \times {10^{22}}\)

The no of atoms of hydrogen will be \(9.452 \times {10^{23}}\)

Step by step solution

01

Determine molecular mass

To calculate no of molecules in 9.213 g of that compound, we have to evaluate the molar mass of that compound.

Element

Quantity

Molar mass

(g/mol element)

Subtotal

(g/mol compound)

C

4

×

12.01

=

48.04

H

10

×

1.008

=

10.08

Molecular mass(g/mol)

=

58.12

02

Determine number of C4H10 molecules 

No. of molecules of that compound in 9.213 g of that compound,

\(\begin{align}9.213{\rm{ g of }}{{\rm{C}}_{\rm{4}}}{{\rm{H}}_{10}} \times \frac{{{\rm{mol of }}{{\rm{C}}_{\rm{4}}}{{\rm{H}}_{10}}}}{{58.12{\rm{ g of }}{{\rm{C}}_{\rm{4}}}{{\rm{H}}_{10}}}} \times \frac{{6.022 \times {{10}^{23}}{\rm{ molecules of }}{{\rm{C}}_{\rm{4}}}{{\rm{H}}_{10}}}}{{{\rm{mol of }}{{\rm{C}}_{\rm{4}}}{{\rm{H}}_{10}}}}\\{\rm{ }} = 9.452 \times {10^{22}}{\rm{molecules of }}{{\rm{C}}_{\rm{4}}}{{\rm{H}}_{10}}\end{align}\)

Hence, no of molecules of C4H10 will be \(9.452 \times {10^{22}}\)

03

Determine number of hydrogen atom

No. of hydrogen atoms,

\(9.452 \times {10^{22}}{\rm{ molecules of }}{{\rm{C}}_4}{{\rm{H}}_{10}} \times \frac{{10{\rm{ H atoms}}}}{{1{\rm{ molecules of }}{{\rm{C}}_4}{{\rm{H}}_{10}}}} = 9.452 \times {10^{23}}{\rm{H atoms}}\)

Hence, the no of atoms of hydrogen will be \(9.452 \times {10^{23}}\)

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