Question

How many moles of sucrose, C₁₂H₂₂O₁₁, are in a 25-g sample of sucrose?

Short answer

No. of moles of sucrose is equal to \(0.073{\rm{ mol}}\)

Step-by-step solution

Determine molecular mass 

To calculate no of moles of sucrose, we have to evaluate the molar mass of sucrose first.

Element	Quantity		Molar mass (g/mol element)		Subtotal (g/mol compound)
C	12	×	12.01	=	144.12
H	22	×	1.008	=	22.176
O	11	×	16.00	=	176.00
			Molecular mass(g/mol)	=	342.296

Determine no of moles

No of moles = \(25{\rm{ g sucrose }} \times {\rm{ }}\frac{{{\rm{mol of sucrose}}}}{{342.296{\rm{ g sucrose}}}} = 0.073{\rm{ mol of sucrose}}\)

Hence, no of moles of sucrose is equal to\(0.073{\rm{ mol}}\)