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Question:What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?

Short Answer

Expert verified

The volume ofC12H22O11stock solution needs 1.9mL.

Step by step solution

01

Summarize the given data

The number of moles of solute before dilution is equal to the number of moles after dilution.

M1V1=M2V2.

Given

M1=0.33MV2=25mLM2=0.025M

02

Determine the volume of the solution required

Find V1, the initial value.

V1=M2V2M1

Substitute the values in the formula above.

V1=(0.025M)25mL0.33M=1.9mL

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