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Use valence bond theory to explain the bonding in\({{\rm{O}}_{\rm{2}}}\). Sketch the overlap of the atomic orbitals involved in the bonds in \({{\rm{O}}_{\rm{2}}}\).

Short Answer

Expert verified

The molecules of oxygen contains a double bond consisting of sigma and pi bond.

Step by step solution

01

Definition of Concept

The sigma bond is formed when two half-filled atomic orbitals involved in the formation of a molecular orbital overlap along the internuclear axis.

The bond formed is a pi-bond when half-filled p-orbitals involved in bond formation overlap sideways.

02

Sketch the overlap of the atomic orbitals involved in the bonds

The bonding in\({{\rm{O}}_{\rm{2}}}\)can be explained in following ways:

A sigma bond and a pi-bond make up the double bond in the oxygen molecule. Two half-filled p-orbitals from each atom overlap along their internuclear axis when two oxygen atoms approach each other, forming a sigma bond. As shown in the diagram, a pi-bond is formed when one atom's second half-filled p-orbital overlaps a similar p-orbital of the other atom sideways.

Therefore, the sigma and pi bonds in oxygen molecules form a double bond.

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Most popular questions from this chapter

Predict the valence electron molecular orbital configurations for the following, and state whether they will be stable or unstable ions.

(a) \({\rm{N}}{{\rm{a}}_{\rm{2}}}^{{\rm{2 + }}}\)

(b) \({\rm{M}}{{\rm{g}}_{\rm{2}}}^{{\rm{2 + }}}\)

(c) \({\rm{A}}{{\rm{l}}_{\rm{2}}}^{{\rm{2 + }}}\)

(d) \({\rm{S}}{{\rm{i}}_{\rm{2}}}^{{\rm{2 + }}}\)

(e) \({\rm{P}}_{\rm{2}}^{{\rm{2 + }}}\)

(f) \({{\rm{S}}_{\rm{2}}}^{{\rm{2 + }}}\)

(g) \({{\rm{F}}_{\rm{2}}}^{{\rm{2 + }}}\)

(h) \({\rm{A}}{{\rm{r}}_{\rm{2}}}^{{\rm{2 + }}}\)

Label the molecular orbital shown as ฯƒ or ฮ , bonding or antibonding, and indicate where the node occurs.


Give the shape that describes each hybrid orbital set:

(a) \({\rm{s}}{{\rm{p}}^{\rm{2}}}\)

(b) \({\rm{s}}{{\rm{p}}^{\rm{3}}}{\rm{d}}\)

(c) sp

(d) \({\rm{s}}{{\rm{p}}^{\rm{3}}}{{\rm{d}}^{\rm{2}}}\)

Strike-anywhere matches contain a layer of \({\rm{KCl}}{{\rm{O}}_{\rm{3}}}\) and a layer of \({{\rm{P}}_{\rm{4}}}{{\rm{S}}_{\rm{3}}}\). The heat produced by the friction of striking the match causes these two compounds to react vigorously, which sets fire to the wooden stem of the match. \({\rm{KCl}}{{\rm{O}}_{\rm{3}}}\) contains the \({\rm{Cl}}{{\rm{O}}_{\rm{3}}}^{\rm{ - }}\) ion. \({{\rm{P}}_{\rm{4}}}{{\rm{S}}_{\rm{3}}}\) is an unusual molecule with the skeletal structure.

  1. Write Lewis structures for \({{\rm{P}}_{\rm{4}}}{{\rm{S}}_{\rm{3}}}\) and the \({\rm{Cl}}{{\rm{O}}_{\rm{3}}}^{\rm{ - }}\) ion.
  2. Describe the geometry about the \({\rm{P}}\) atoms, the \({\rm{S}}\) atom, and the \({\rm{Cl}}\) atom in these species.
  3. Assign a hybridization to the \({\rm{P}}\) atoms, the \({\rm{S}}\)atom, and the \({\rm{Cl}}\) atom in these species.
  4. Determine the oxidation states and formal charge of the atoms in \({{\rm{P}}_{\rm{4}}}{{\rm{S}}_{\rm{3}}}\) and the \({\rm{Cl}}{{\rm{O}}_{\rm{3}}}^{\rm{ - }}\) ion.

How are the following similar, and how do they differ?

(a) ฯƒ molecular orbitals and ฯ€ molecular orbitals

(b) ฯˆ for an atomic orbital and ฯˆ for a molecular orbital (c) bonding orbitals and antibonding orbitals

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