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Identify the hybridization of each carbon atom in the following molecule. (The arrangement of atoms is given; you need to determine how many bonds connect each pair of atoms.)

Short Answer

Expert verified

Two carbon atoms have been \({\rm{s}}{{\rm{p}}^{\rm{3}}}\) hybridised, two carbon atoms have been \({\rm{s}}{{\rm{p}}^{\rm{2}}}\)hybridised, and two carbon atoms have been \({\rm{sp}}\) hybridised.

Step by step solution

01

Define atom

Atom is the fundamental unit of any element. A.It cannot be broken down further by chemical processes.

02

Explanation

This is the structure created by linking the atoms with the proper number of bonds, and each carbon atom's hybridization is indicated below.

Therefore, \({\rm{s}}{{\rm{p}}^{\rm{3}}}\) hybridization of two carbons, \({\rm{s}}{{\rm{p}}^{\rm{2}}}\) hybridization of two carbons, and \({\rm{sp}}\) hybridization of two carbons.

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Most popular questions from this chapter

Why is the concept of hybridization required in valence bond theory?

Calculate the bond order for an ion with this configuration: \({\left( {{{\bf{\sigma }}_{{\bf{2s}}}}} \right)^{\bf{2}}}{\left( {{\bf{\sigma }}_{{\bf{2s}}}^{\bf{*}}} \right)^{\bf{2}}}{\left( {{{\bf{\sigma }}_{{\bf{2px}}}}} \right)^{\bf{2}}}{\left( {{{\bf{\pi }}_{{\bf{2py}}}}{\bf{,}}{{\bf{\pi }}_{{\bf{2pz}}}}} \right)^{\bf{4}}}{\left( {{\bf{\pi }}_{{\bf{2py}}}^{\bf{*}}{\bf{,\pi }}_{{\bf{2pz}}}^{\bf{*}}} \right)^{\bf{3}}}\).

Using the MO diagrams, predict the bond order for the stronger bond in each pair:

B2or B2+

F2orF2+

O2 or O22+

C2+or C2-

Why are bonding molecular orbitals lower in energy than the parent atomic orbitals?

Sulfuric acid is manufactured by a series of reactions represented by the following equations:

\(\begin{array}{l}{{\rm{S}}_{\rm{8}}}{\rm{(s) + 8}}{{\rm{O}}_{\rm{2}}}{\rm{(g)}} \to {\rm{8S}}{{\rm{O}}_{\rm{2}}}{\rm{(g)}}\\{\rm{2S}}{{\rm{O}}_{\rm{2}}}{\rm{(g) + }}{{\rm{O}}_{\rm{2}}}{\rm{(g)}} \to {\rm{2S}}{{\rm{O}}_{\rm{3}}}{\rm{(g)}}\\{\rm{S}}{{\rm{O}}_{\rm{3}}}{\rm{(g) + }}{{\rm{H}}_{\rm{2}}}{\rm{O(l)}} \to {{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}{\rm{(l)}}\end{array}\)

Draw a Lewis structure, predict the molecular geometry by VSEPR, and determine the hybridization of sulfur for the following:

(a) circular \({{\rm{S}}_{\rm{8}}}\)molecule

(b) \({\rm{S}}{{\rm{O}}_{\rm{2}}}\)molecule

(c) \({\rm{S}}{{\rm{O}}_{\rm{3}}}\)molecule

(d) \({{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}\)molecule (the hydrogen atoms are bonded to oxygen atoms)

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