Chapter 14: Q103 E (page 836)
Which acid in Table 14.2 is most appropriate for preparation of a buffer solution with a pH of 3.1? Explain your choice.
Short Answer
\(HN{O_2} \) would be the best choice for buffer.
Chapter 14: Q103 E (page 836)
Which acid in Table 14.2 is most appropriate for preparation of a buffer solution with a pH of 3.1? Explain your choice.
\(HN{O_2} \) would be the best choice for buffer.
All the tools & learning materials you need for study success - in one app.
Get started for freePropionic acid, \({C_2}{H_5}C{O_2}H\left( {{K_a} = 1.34 \times 1{0^{ - 5}}} \right)\), is used in the manufacture of calcium propionate, a food preservative. What is the hydronium ion concentration in a \(0.698 M\) solution of \({C_2}{H_5}C{O_2}H ? \)
Which of the following will increase the percentage of HF that is converted to the fluoride ion in water?
(a) Addition of \(NaOH\)
(b) Addition of \(HCl\)
(c) Addition of \(NaF\)
From the equilibrium concentrations given, calculate \({K_a}\)for each of the weak acids and \({K_b}\)for each of the weak bases.
\(\begin{aligned}(a)N{H_3}:\left( {O{H^ - }} \right) = 3.1 \times 1{0^{ - 3}}M\left( {NH_4^ + } \right) = 3.1 \times 1{0^{ - 3}}M;\left( {N{H_3}} \right) = 0.533M;\\(b)HN{O_2}:\left( {{H_3}{O^ + }} \right) = 0.011M;\left( {NO_2^ - } \right) = 0.0438M;\left( {HN{O_2}} \right) = 1.07M;\\(c){\left( {C{H_3}} \right)_3}\;N:\left( {{{\left( {C{H_3}} \right)}_3}\;N} \right) = 0.25M;\left( {{{\left( {C{H_3}} \right)}_3}N{H^ + }} \right) = 4.3 \times 1{0^{ - 3}}M;\left( {O{H^ - }} \right) = 4.3 \times 1{0^{ - 3}}M;\\(d)N{H_4} + :\left( {N{H_4} + } \right) = 0.100M;\left( {N{H_3}} \right) = 7.5 \times 1{0^{ - 6}}M;\left( {{H_3}{O^ + }} \right) = 7.5 \times 1{0^{ - 6}}M\end{aligned}\)
\(\begin{aligned}\left( {N{H_3}} \right) = 7.5 \times 1{0^{ - 6}}M\\\left( {{H_3}{O^ + }} \right) = 7.5 \times 1{0^{ - 6}}M\end{aligned}\)
How much solid \({\bf{NaC}}{{\bf{H}}_{\bf{3}}}{\bf{C}}{{\bf{O}}_{\bf{2}}} \bullet {\bf{3}}{{\bf{H}}_{\bf{2}}}{\bf{O}}\) must be added to \({\bf{0}}.{\bf{300}}{\rm{ }}{\bf{L}}\) of a \({\bf{0}}.{\bf{50}}{\rm{ }}{\bf{M}}\) acetic acid solution to give a buffer with a pH of 5.00? (Hint: Assume a negligible change in volume as the solid is added.)
What two common assumptions can simplify calculation of equilibrium concentrations in a solution of a weak acid?
What do you think about this solution?
We value your feedback to improve our textbook solutions.