Question

Give the oxidation number of nitrogen in the following:

$$\begin{gathered} \left(a\right)\mathit{N}{\mathit{H}}_{\mathbf{2}}\mathit{O}\mathit{H} \\ \left(b\right){\mathit{N}}_{\mathbf{2}}{\mathit{F}}_{\mathbf{4}} \\ \left(c\right)\mathit{N}{\mathit{H}}_{\mathbf{4}}^{\mathbf{+}} \\ \left(d\right)\mathit{H}\mathit{N}\mathit{O} \end{gathered}$$

Short answer

Answer: You need to provide the oxidation no of nitrogen for the given compounds

Step-by-step solution

Oxidation state of nitrogen in NH2OH 

Oxidation state of Hydrogen is +1.

Oxidation state of Oxygen is -2.

Let, oxidation state of nitrogen in NH₂OH is x.

No you can write,

$$\begin{gathered} x+2\left(+1\right)+\left(-2\right)+\left(+1\right)=0 \\ x=-1 \end{gathered}$$

Hence, oxidation state of nitrogen in NH₂OH is -1.

Oxidation state of nitrogen in N2F4 

Oxidation state of Flurine is -1.

Let, oxidation state of nitrogen in N₂F₄ is y.

No you can write,

$$\begin{gathered} 2y+4\left(-1\right)=0 \\ 2y=+4 \\ y=+2 \end{gathered}$$

Hence, oxidation state of nitrogen in N₂F₄ is +2.

Oxidation state of nitrogen in NH3+ 

Oxidation state of Hydrogen is +1.

Let, oxidation state of nitrogen in NH₃⁺is z.

No you can write,

$$\begin{gathered} z+4\left(+1\right)=+1 \\ z=-3 \end{gathered}$$

Hence, oxidation state of nitrogen in NH₃⁺is -3.

Oxidation state of nitrogen in HNO2 

Oxidation state of Hydrogen is +1.

Oxidation state of Oxygen is -2.

Let, oxidation state of nitrogen in HNO₂is k.

No you can write,

$$\begin{gathered} \left(+1\right)+k+2\left(-2\right)=0 \\ k=+3 \end{gathered}$$

Hence, oxidation state of nitrogen in HNO₂is +3.