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The KSP of PbCl2 is 1.7×10-5 at 25°C. What is ΔG°? Is it possible to prepare a solution that contains Pb2+(aq)and Cl-(aq), at their standard-state concentrations?

Short Answer

Expert verified

For this reaction, the ΔGrxn° is 27.21kJ/mol.

When the PbCl2 salt is dissolved, the reaction is not spontaneous, and it is impossible to prepare 1M concentration solutions.

Step by step solution

01

Definition of standard-state concentrations

When the concentration of a solute is 1 M, it is considered to be under standard state conditions.

02

Calculate ΔGrxn°

Because the solubility-product constant is known and the temperature is known, the reaction's Gibb's free energy can be computed as

ΔG°=RTlnKp

Then, at 298K(25°C)

ΔG°=8.314JmolK298Kln(1.7105)ΔG°=2.721104Jmol=27.21kJmol.

For this reaction, theΔGrxn° is 27.21kJ/mol.

03

Whether reaction is spontaneous or not

At standard conditions, the reaction is non-spontaneous because ΔG°>0. As a result, preparing a solution of standard concentration - 1M would be impossible.

In ordinary conditions, the response quotient Q is

Q=[Pb2+][Cl]2Q=[1M]Invalid <msup> elementQ=1.

As a result, the forward reaction is non-spontaneous as Q>>Kspp. As a result, preparing 1M concentrations after dissolving PbCl2 salt is difficult.

Therefore, reaction is not spontaneous and it is impossible to prepare 1M concentration solutions upon dissolution of PbCl2 salt.

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