Question

Molten beryllium chloride reacts with chloride ion from molten $\mathbf{NaCl}$ to form the ${{\mathbf{BeCl}}_4}^{2-}$ion, in which the Be atom attains an octet. Show the net ionic reaction with Lewis structures

Short answer

The ionic reaction$\mathbf{4}\mathbf{NaCl}\mathbf{+}\mathbf{Be}\mathbf{-}\mathbf{-}\mathbf{-}\mathbf{-}{\mathbf{BeCl}}_4{{}^{2-}}^{}$

Step-by-step solution

Lewis Structure

A Lewis structure can be defined as the basic structure of a molecule that used the valence electron of each atom involved. In Lewis’s structure, the least electronegative atom will be the central atom.

The octet rule may be defined as themaximum of 8 electronsthat can be filled in an orbital of an atom. It can be completed by sharing or giving the electrons to become stable.

Reaction

$\begin{array}{l}\mathbf{NaCl}\mathbf{-}\mathbf{-}\mathbf{-}{\mathbf{Na}}^{+}\mathbf{+}{\mathbf{Cl}}^{-}\\ {{\mathbf{BeCl}}_2}^{-}\mathbf{+}\mathbf{2}{\mathbf{Cl}}^{-}\mathbf{-}\mathbf{-}\mathbf{-}{{\mathbf{BeCl}}_4}^{2-}\end{array}$

The ionic reaction reacts with each other in the form of ions and is very easy to react in solution form