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Calculate the molarity of each aqueous solution:

(a) 25.5 mL of 6.25 M HCl diluted to 0.500 L with water

(b) 8.25 mL of 2.00ร—10-2M KI diluted to 12.0 mL with water

Short Answer

Expert verified
  1. The molarity of the HCl is 0.32M after dilution.
  2. The molarity of the KI is 0.1375M after dilution.

Step by step solution

01

Concentration of the Solution

Solution can be formed from thedissolution of the solute in the solvent.

The number of moles of solute remains unchanged after dilution. The number of moles of solute is the product of molarity of the solution and the volume of the solution.

Molarityโ€ŠEquation,M1ร—V1=M2ร—V2

Number of moles can be defined as the ratio of the mass of the atom/molecule and molar mass of the atom/molecule.

Numberโ€Šofโ€ŠMoles=MassMolarโ€ŠMass

02

Subpart (a)

The final volume of HCl solution is V2=0.500โ€ŠL

Initial molarity of HCl at M1=6.25โ€ŠM

Initial volume is V1=0.025โ€ŠmL

Molarity of solution after dilution be M2.

role="math" localid="1659270756591" Molarityโ€ŠEquation,M1ร—V1=M2ร—V2

role="math" localid="1659270733316" 6.25Mร—0.0255L=M2ร—0.500LM2=6.25Mร—0.0255L0.500LM2=0.32M

03

Subpart (b)

Initial volume of the solution is V1=8.25โ€ŠmL=0.00825โ€ŠL

Initial molarity of KI solution

M1=2.00ร—10-2โ€ŠM=0.02โ€ŠM

Volume of Solution after dilution is V2=0.012โ€ŠL

Molarity of solution after dilution be M2.

Molarityโ€ŠEquation,M1ร—V1=M2ร—V2

0.02Mร—0.00825L=M2ร—0.012LM2=0.02Mร—0.00825L0.012LM2=0.1375M

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