Question

AH nucleus decays with an energy ofMeV. Convert this energy into (a) electron volts; (b) joules.

Short answer

$$\begin{gathered} \text{a)}1.861\times {10}^4\text{eV} \\ \text{b)2.981}\times {10}^{-15}\text{J} \end{gathered}$$

Step-by-step solution

Step 1:To convert (a) electron volts (b) joules.

(a)

We have to convert $\text{0.01861MeV}$into electron volts.

$\text{1MeV}\text{=}{\text{10}}^{\text{6}}\text{eV}$

$\text{0.01861MeV}\text{=0.01861MeV×}\frac{{\text{10}}^{\text{6}}\text{eV}}{\text{1MeV}}{\text{=1.861×10}}^{\text{4}}\text{eV}$

(b)

We have to convert $\text{0.01861MeV}$into joules.

$\text{1MeV}\text{=}{\text{1.602×10}}^{\text{- 13}}\text{J}$

$\text{0.01861MeV}\text{=}\text{0.01861MeV×}\frac{{\displaystyle {\text{1.602×10}}^{\text{- 13}}\text{J}}}{{\displaystyle \text{1MeV}}}\text{=}\text{2.981}{\times 10}^{\text{- 15}}\text{J}$