Question

What oxidation slates does $\mathbf{\text{Xe}}$ show in its compounds?

Short answer

Xenon has the most complex chemistry of Group $18$, with oxidation states of $+2,+4,+6,$ and $+8$ in the compounds it forms.

Step-by-step solution

A concept of oxidation:

The total number of electrons that an atom gets or loses to establish a chemical connection with another atom is referred to as itsoxidation number.

What oxidation slates does Xe exhibit in its compounds?

Xenon's $\left(\text{Xe}\right)$ valence electron configuration is $5s^{2}5p^6$.

In its compounds, xenon has even oxidation states.

Xenon's known compounds are ${\text{XeF}}_{\text{2}}{\text{,XeF}}_{\text{4}}{\text{,XeF}}_{\text{6}}{\text{,XeO}}_{\text{3}}$and ${\text{XeO}}_{\text{4}}$.

The oxidation state of $\text{Xe}$in ${\text{XeF}}_{\text{2}}$is $\text{+2}$.

The oxidation state of $\text{Xe}$in ${\text{XeF}}_4$is $\text{+4}$.

The oxidation state of $\text{Xe}$ in ${\text{XeF}}_6$ is $\text{+6}$.

The oxidation state of $\text{Xe}$in ${\text{XeO}}_3$ is $\text{+6}$.

The oxidation state of $\text{Xe}$in ${\text{XeO}}_4$is $\text{+8}$.

Conclusion:

As a result, the xenon's oxidation states of xenon in its compounds are $+2,+4,+6,$ and $+8$.