Login Registrieren

Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Chapter 24: Q24.52 P (page 1104)

Why does bombardment with protons usually require higher energies than bombardment with neutrons?

Short Answer

Expert verified

To overcome the repulsion, more energy is necessary.

Step by step solution

01

Protons

The protons are the subatomic particles with positive charge. They deflect in electric and magnetic fields.

02

Explanation

The protons are the subatomic particles with positive charge. They deflect in electric and magnetic fields.

Due to interaction with like charges, protons are repelled from the target nuclei.

Protons and the nucleus is positively charged, they will repel. Higher energy is required to overcome the repulsion.

Hence, higher energy is required to overcome the repulsion.

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Irene and Frederic Joliot-Curie converted $_{13}^{27}$ Al to $_{15}^{30}$ P in . Why was this transmutation signiﬁcant?

The isotope ${^{212}}_{83} Bi$ has a half-life of $1.01$ yr. What mass (in mg) of a $2.00$ -mg sample will remain after ${3.75×10}^{3} h$ ?

Due to decay of $^{40} K$ , cow’s milk has a speciﬁc activity of about ${6x10}^{-11}$ mCi per milliliter. How many disintegrations of $^{40} K$ nuclei are there per minute in an $8.0$ -oz glass of milk?

If $6 .40 \times 10^{- 9} mol$ of $^{176} W$ emits $1 .07 \times 10^{15} β^{+}$ in $1 .00 h$ , what is the decay constant?

Question: ${}^{237}N p$ is the parent nuclide of a decay series that starts with $α$ -emission, followed by $β^{-}$ emission, and then two more emissions. Write a balanced nuclear equation for each step?

See all solutions

Recommended explanations on Chemistry Textbooks

Physical Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Organic Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free