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Give two reasons to measure initialrates in a kinetic study.

Short Answer

Expert verified

The answer is,

1) To calculate the overall rate of a reaction.

2) To calculate many other kinetic parameters.

Step by step solution

01

Rate of a reaction

The rate of a reaction is the speed at which the reactants undergo product formation at a constant temperature. The initial rate is the rate at the initial point of the reaction, where the reactant concentration is introduced.

02

Explanation

The two reasons to measure the initial rate in a kinetic study is as given below.

1) The overall rate of a reaction is calculated by measuring the rate of the forward reaction and that of the reverse reaction and taking the difference of both. This is done by finding the initial rate, the instantaneous rate at the initial point of addition of reactants to avoid complications of the calculations.

2) The initial rate of the reaction is used to calculate many other kinetic parameters.

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Most popular questions from this chapter

For the reaction , how many unique collisions between A and B are possible if 1.01 mol of A(g) and 2.12 mol of B(g) are present in the vessel?

Even when a mechanism is consistent with the rate law, later work may show it to be incorrect. For example, the reaction between hydrogen and iodine has this rate law: rate=k[H2][I2] . The long-accepted mechanism had a single bimolecular step; that is, the overall reaction was thought to be elementary:

H2(g)+I2(g)2HI(g)

In the 1960s, however, spectroscopic evidence showed the presence of free I atoms during the reaction. Kineticists have since proposed a three-step mechanism:

(1)I2(g)2I(g)[fast](2)H2(g)+I(g)H2I(g)[fast](3)H2I(g)+I(g)2HI(g)[slow]

Show that this mechanism is consistent with the rate law.

To determine its rate law. Assuming that you have a valid experimental procedure for obtaining [A2] and [B2] at various times, explain how you determine

A2(g)+B2(g)2AB(g)

(a) the initial rate,

(b) the reaction orders, and

(c) the rate constant.

Iodide ion reacts with chloromethane to displace chloride ion in a common organic substitution reaction:

I-+CH3CICH3I+CI-

(a) Draw a wedge-bond structure of chloroform and indicate the most effective direction of I-attack.

(b) The analogous reaction with 2-chlorobutane [Figure P16.107(b)] results in a major change in specific rotation as measured by polarimetry. Explain, showing a wedge-bond structure of the product.

(c) Under different conditions, 2-chlorobutane loses CI-in a rate-determining step to form a planar intermediate [Figure P16.107(c)]. This cationic species reacts with HI and then loses H to form a product that exhibits no optical activity. Explain, showing a wedge-bond structure.

If the temperature in Problem 16.60 is increased to 50C, by what factor does the fraction of collisions with energy equal to or greater than the activation energy change?

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