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In a gaseous equilibrium, the reverse reaction occurs whenQc>Kc. What occurs in aqueous solution whenQsp>Ksp?

Short Answer

Expert verified

When the Qsp value is greater than Ksp value, that means that we have a higher concentration of Pb2+ ions in the solution, than we would have in the equilibrium state. This means that the direction of the dissolution equation will be shifted from right to left and more of PbF 2 (s) will be formed.

Step by step solution

01

Concept Introduction

The Qsp-ion-product expression is obtained by multiplying the concentrations of ions generated by the dissolution of a chemical. When a solution is saturated, the Kspvalue is referred to as the value (solubility-product constant).

MX2> >M2 ++ 2X-Ksp =[M2 +][X-]2

02

Explanation

To tackle this problem, we can formulate the dissolution equation forPbF2as follows:

PbF2(s) > > Pb2 +(aq) + 2F-(aq)Qsp =Pb2 +F-2

When theQspvalue is greater than theKspvalue, the concentration ofPb2 +andF-ions in the solution is higher than it would be in the equilibrium state.

This indicates that the dissolution equation will be moved from right to left, resulting in more PbF2(s)being created according to the Le Chatelier principle, and we will be able to extract this precipitate from the solution.

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