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Explain how strong acid–strong base, weak acid–strong base, and weak base–strong acid titrations using the same concentrations differ in terms of (a) the initial pH and (b) the pH at the equivalence point. (The component in italics is in the flask.)

Short Answer

Expert verified

(a) strong acid-strong base < weak acid-strong base < weak base-strong acid.

(b) strong acid-weak base < strong acid-strong base < weak acid-strong base.

Step by step solution

01

Define equivalence point

In a titration, an equivalence point is reached when the amount of titrant administered is sufficient to totally neutralize an analyte solution.

02

Explanation

(a )The initial pH:

  • A strong acid with a strong base (strong acid is in the flask)As only the strong acid (with a lot of H3O+ions) is present in the flask, the pH value will be much lower than 7. pH<<7
  • Weak acid-strong base (weak acid is in the flask). Because the flask contains only the weak acid (and there aren't many H3O+ions), the pH value will be significantly closer to 7 than in the previous case. pH7.
  • Strong acid-weak base (weak base is in the flask). The pH value is very close to 7 or maybe slightly higher than 7 because the flask contains only a weak base (more OH-than H3O+ions) pH7.

The following is a list of the pH levels in ascending order: strong acid-strong base < weak acid-strong base < weak base-strong acid.

03

Explanation

(b)The pH at equivalence point:

  • A strong acid with a strong base (strong acid is in the flask). An added base always neutralizes an acid at an equivalence point, therefore, the number of moles of added OH-ions equals the number of moles of H3O+. The pH value is neutral at the equivalence point because the solution contains an anion of a strong acid and a cation of a strong base (which does not react with water). pH=7.
  • weak acid-strong base (weak acid is in the flask). In this example, the solution consists of the strong base's cation, which does not react with water, and the weak acid's anion, which reacts with water, takes H+, and generates OH-A-+H2O > > HA + OH-. The solution will be basic at the equivalence point because only OH-ions are generated.
  • Strong acid-weak base (weak base is in the flask). The solution in this scenario consists of an anion of a strong acid that does not react with water and a cation of the weak base that donates a proton to the water and forms H3O+at an equivalence point. As a result, the solution is slightly acidic at the equivalence point.

The order in which the pH levels rises will be:

Strong acid-weak base < strong acid-strong base < weak acid-strong base.

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Most popular questions from this chapter

An environmental technician collects a sample of rainwater. Back in the lab, hermeter isn't working, so she uses indicator solutions to estimate the. A piece of litmus paper turns red, indicating acidity, so she divides the sample into thirds and obtains the following results: thymol blue turns yellow; bromophenol blue turns green; and methyl red turns red. Estimate theof the rainwater.

What is the component concentration ratio, [CH3COO-]/[CH3COOH], of a buffer that has a pH of 4.39 ( Kaof [CH3COOH]=1.8×10-5)?

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(a) Magnesium hydroxide or nickel (II)hydroxide

(b) Lead (II)sulphide or copper (II)sulphide

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Amino acids [general formula NH2CH(R)COOH]can be considered polypro tic acids. In many cases, the R group contains additional amine and carboxyl groups.

(a) Can an amino acid dissolved in pure water have a protonated localid="1663345833873" COOH group and an unprotonated localid="1663345865389" NH2group

localid="1663345870225" (KXofCOOHgroup=4.47×10-3;KbofNH2group=6.03×10-3y?

Use glycine, localid="1663345879880" NH3CH3COOH, to explain why.

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(d) Thelocalid="1663345947279" Rgroup of glutamic acid localid="1663345920800" -CH2CH2COOH(pKa=4.07).of the forms of glutamic acid that are shown below, which predominates at,localid="1663345941655" (1)localid="1663345993071" pH1(2) localid="1663345925494" physaiologicalpHH(-7),

and (3) localid="1663345936358" pH13?

Quantitative analysis of Cl-ion is often performed by a titration with silver nitrate, using sodium chromate as an indicator. As standardized AgNO3is added, both white AgCl and red role="math" localid="1663261461482" Ag2CrO4 precipitate, but so long as someCl-remains, the Ag2CrO4redissolves as the mixture is stirred. When the red color is permanent, the equivalence point has been reached.

(a) Calculate the equilibrium constant for the reaction

data-custom-editor="chemistry" 2AgCl(s)+CrO42-(aq)Ag2CrO4(s)+2Cl-(aq)

(b) Explain why the silver chromate redissolves.

(c) If 25.00cm3 of 0.1000MNaClis mixed with 25.00cm3of 0.1000MAgNO3, what is the concentration of Ag+remaining in solution? Is this sufficient to precipitate any silver chromate?

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