Chapter 24: Problem 57
The half-life of polonium-218 is 3.0 min. If you start with 20.0 g, how long will it be before only 1.0 g remains?
Short Answer
Expert verified
It will take approximately 12.96 minutes for the sample of polonium-218 to decay from 20.0 g to 1.0 g.
Step by step solution
01
Identify the relevant variables and constants
Initial mass (m_initial) = 20.0 g
Final mass (m_final) = 1.0 g
Half-life (t_half) = 3.0 min
02
Use the half-life formula to determine the number of half-lives that have passed
The formula relating initial mass, final mass and the number of half-lives is:
m_final = m_initial * (1/2)^n
Where n is the number of half-lives passed. We need to solve for n:
1.0 = 20.0 * (1/2)^n
03
Solve for the number of half-lives (n)
We can solve the above equation for n:
(1/2)^n = 1.0 / 20.0
We can use logarithms to calculate 'n', specifically using natural logarithm 'ln':
n = ln(1.0 / 20.0) / ln(1/2)
Now calculate n:
n ≈ 4.32
04
Calculate the total time it takes for the sample to decay
Since we have the value of n (number of half-lives), we can now find the total time it took for the mass to decay from 20.0 g to 1.0 g:
time = n * t_half
time = 4.32 * 3.0
time ≈ 12.96 min
So, it will take approximately 12.96 minutes for the sample of polonium-218 to decay from 20.0 g to 1.0 g.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polonium-218
Polonium-218 is a naturally occurring radioactive isotope. It belongs to the polonium family of elements. What makes it particularly interesting is its short half-life of just three minutes.
This means that Polonium-218 decays rapidly into other elements in a relatively short period. This rapid decay is an essential property for calculating how long it takes for a given amount of this substance to decrease to a specified quantity.
Some fascinating facts about Polonium-218:
- It's part of the uranium-238 decay series, where uranium ultimately breaks down into lead through a chain of decay steps.
- Polonium-218 emits radioactive alpha particles during its decay process.
- It plays a minor role in determining the age of uranium-rich minerals.
Radioactive Decay
Radioactive decay is a natural process where unstable atomic nuclei lose energy by emitting radiation. There are different types of radioactive decay, including alpha decay, beta decay, and gamma decay.
In the case of Polonium-218, it undergoes alpha decay. Here's how this process could be described:
- During alpha decay, Polonium-218 emits an alpha particle, which comprises 2 protons and 2 neutrons.
- As a result of emitting this alpha particle, the nucleus loses some of its mass, becoming a new element altogether.
- This transformation is part of a series of decays each element in this series undergoes, until a stable element, such as lead, is formed.
Natural Logarithm
Logarithms are mathematical tools used to simplify the handling of exponential relationships. The natural logarithm, denoted as ln, utilizes the base of 'e' (approximately 2.718) and is especially useful in continuous growth or decay situations.When dealing with radioactive decay and half-lives, the natural logarithm can help us solve for the number of half-lives (n) a substance has undergone. Here's the connection:
- The equation relating initial mass, final mass, and half-lives uses an exponential relationship: \( m_{final} = m_{initial} \cdot (1/2)^n \).
- To solve for the unknown 'n', the equation is rearranged using the natural logarithm: \( n = \frac{\ln(m_{final} / m_{initial})}{\ln(1/2)} \).
- This principle allows us to calculate 'n' and, subsequently, the time taken for a radioactive substance to decay by using its half-life.