Chapter 11: Problem 40
Why are coefficients used in mole ratios instead of subscripts?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 11: Problem 40
Why are coefficients used in mole ratios instead of subscripts?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeIdentify which type of yield- theoretical yield, actual yield, or percent yield - is a measure of the efficiency of a chemical reaction.
Antacids Magnesium hydroxide is an ingredient in some antacids. Antacids react with excess hydrochloric acid in the stomach to relieve indigestion. ___ \(\mathrm{Mg}(\mathrm{OH})_{2}+\) ___ \(\mathrm{HCl} \rightarrow\) ___ \(\mathrm{MgCl}_{2}+\) ___ \(\mathrm{H}_{2} \mathrm{O}\) a. Balance the reaction of \(\mathrm{Mg}(\mathrm{OH})_{2}\) with \(\mathrm{HCl}\) . b. Write the mole ratio that would be used to determine the number of moles of MgCl_ produced when HCl reacts with \(\mathrm{Mg}(\mathrm{OH})_{2}\)
Challenge Sulfuric acid \(\left(\mathrm{H}_{2} \mathrm{SO}_{4}\right)\) is formed when sulfur dioxide (SO_{2} ) reacts with oxygen and water. a. Write the balanced chemical equation for the reaction. b. How many moles of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) is produced from 12.5 \(\mathrm{moles}\) of \(\mathrm{SO}_{2} ?\) c. How many moles of \(\mathrm{O}_{2}\) are needed?
Lithium reacts spontaneously with bromine to produce lithium bromide. Write the balanced chemical equation for the reaction. If 25.0 g of lithium and 25.0 g of bromine are present at the beginning of the reaction, determine a. the limiting reactant. b. the mass of lithium bromide produced. c. the excess reactant and the excess mass.
Chlorine forms from the reaction of hydrochloric acid with manganese(IV) oxide. The balanced equation is: $$\mathrm{MnO}_{2}+4 \mathrm{HCl} \rightarrow \mathrm{MnCl}_{2}+\mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O}$$ Calculate the theoretical yield and the percent yield of chlorine if 86.0 \(\mathrm{g}\) of \(\mathrm{MnO}_{2}\) and 50.0 \(\mathrm{g}\) of HCl react. The actual yield of \(\mathrm{Cl}_{2}\) is 20.0 \(\mathrm{g}\)
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