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List the four steps used in solving stoichiometric problems.

Short Answer

Expert verified
1. Write a balanced equation for the chemical reaction. 2. Convert given information into moles using appropriate conversion factors. 3. Apply the mole ratio from the balanced equation to determine moles of other substances. 4. Convert moles of desired substance back to the requested units using conversion factors.

Step by step solution

01

Write a balanced equation

Before starting, make sure you have a balanced chemical equation for the reaction. Without a balanced equation, you won't be able to determine proper ratios of the reactants and products involved in the problem.
02

Convert given information into moles

To solve stoichiometric problems, it's essential to work with moles because mole ratios are derived from the balanced chemical equation. Therefore, the given information – whether it's mass, volume (for gases), or concentration (for solutions) – should be converted into moles using appropriate conversion factors (molar mass, molar volume, or molarity).
03

Apply the mole ratio from the balanced equation

Once the given information has been converted into moles, use the mole ratio obtained from the balanced chemical equation to determine the number of moles of the other substances involved in the reaction. To do so, multiply the moles of the given substance by the stoichiometric coefficients in the balanced equation.
04

Convert moles back to desired units

After finding the number of moles of the desired substance, convert them back into the units requested in the problem (mass, volume, or concentration). Use the corresponding conversion factors for this step (molar mass, molar volume, or molarity). By following these four steps, you will be able to solve stoichiometric problems involving various types of chemical reactions and substances. Remember that practicing and understanding the concepts behind each step is critical for success in solving stoichiometry problems.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balanced Chemical Equation
Understanding the balanced chemical equation is the cornerstone of solving stoichiometric problems in chemistry. A balanced chemical equation ensures that the same number of atoms for each element is present on both sides of the equation, adhering to the law of conservation of mass. This balance is achieved by adjusting coefficients, which are numbers placed in front of the chemical formulas.
In the balanced equation, these coefficients also represent the mole ratio between the substances involved in the reaction. For instance, in the equation \( 2H_2 + O_2 \rightarrow 2H_2O \) the coefficients indicate that 2 moles of hydrogen gas react with 1 mole of oxygen gas to produce 2 moles of water. A key tip for students is to always double-check whether the chemical equation is balanced before proceeding with further calculations, as an unbalanced equation will lead to incorrect results.
Mole Ratio
The mole ratio is a crucial aspect when working with stoichiometric calculations. Derived from the balanced chemical equation, it tells us the proportional relationship between the amounts in moles of each reactant and product in a chemical reaction. For example, the mole ratio of hydrogen to oxygen in the synthesis of water is \( 2:1 \) based on the equation provided above.
To apply the mole ratio, ensure that you first convert all given quantities to moles. Once you have the moles, you can use the mole ratio to find out how many moles of another reactant or product can be formed or are needed. It's essentially like a recipe - if you know how much of one ingredient you have, you can figure out how much of another ingredient you'll need to complete the recipe.
Conversion Factors
Conversion factors are the bridges that allow you to convert between different units of measurement. They are essential when you are dealing with quantities given in units other than moles, such as grams or liters. For example, the molar mass of a substance, given in grams per mole (g/mol), is a conversion factor that can be used to convert grams to moles and vice versa.
To use a conversion factor, write out the factor in a fraction that allows the units you want to get rid of to cancel out. For instance, if you want to convert 18 grams of water to moles, you would use the molar mass of water (approximately \(18 g/mol\)) and set up the conversion like this: \( \frac{18\,grams}{1} \times \frac{1\,mole}{18\,grams} = 1\,mole \) of water. Understanding how to create and use conversion factors accurately is a key skill in solving stoichiometry problems.
Molarity
When dealing with solutions in chemistry, molarity (M) becomes an important concept for stoichiometric problems. It is a measure of concentration, defined as the number of moles of a solute dissolved in one liter of solution. Molarity can serve as a conversion factor to convert between the volume of a solution and the amount in moles of the solute.
To calculate molarity, use the formula \( M = \frac{n}{V} \) where \( n \) is the number of moles of solute and \( V \) is the volume of the solution in liters. Conversely, if the molarity and volume of the solution are known, the number of moles of solute can be calculated as \( n = M \times V \) which is useful when the problem involves reactions in an aqueous environment. Remember, molarity is only accurate when temperature is constant, as solution volume can change with temperature fluctuations.

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Most popular questions from this chapter

Analyze Tetraphosphorus trisulphide \(\left(\mathrm{P}_{4} \mathrm{S}_{3}\right)\) is used in the match heads of some matches. It is produced in the reaction \(8 \mathrm{P}_{4}+3 \mathrm{S}_{8} \rightarrow 8 \mathrm{P}_{4} \mathrm{S}_{3}\) Determine which of the following statements are incorrect, and rewrite the incorrect statements to make them correct. a. 4 mol \(P_{4}\) reacts with 1.5 mol \(S_{8}\) to form 4 mol \(P_{4} S_{3}\) b. Sulfur is the limiting reactant when 4 \(\mathrm{mol} \mathrm{P}_{4}\) and 4 \(\mathrm{mol} \mathrm{S}_{8}\) react. c. 6 mol \(P_{4}\) reacts with 6 mol \(S_{8},\) forming 1320 \(\mathrm{g} \mathrm{P}_{4} \mathrm{S}_{3}\)

Phosphorus \(\left(P_{4}\right)\) is commercially prepared by heating a mixture of calcium phosphate (CaSiO \(_{3} ),\) sand \(\left(\mathrm{SiO}_{2}\right)\) and coke (C) in an electric furnace. The process involves two reactions. $$ \begin{array}{c}{2 \mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(\mathrm{s})+6 \mathrm{SiO}_{2}(\mathrm{s}) \rightarrow 6 \mathrm{CaSiO}_{3}(1)+\mathrm{P}_{4} \mathrm{O}_{10}(\mathrm{g})} \\\ {\mathrm{P}_{4} \mathrm{O}_{10}(\mathrm{g})+10 \mathrm{C}(\mathrm{s}) \rightarrow \mathrm{P}_{4}(\mathrm{g})+10 \mathrm{CO}(\mathrm{g})}\end{array} $$ The \(\mathrm{P}_{4} \mathrm{O}_{10}\) produced in the first reaction reacts with an excess of coke (C) in the second reaction. Determine the theoretical yield of \(\mathrm{P}_{4}\) if 250.0 \(\mathrm{g}\) of \(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) and 400.0 \(\mathrm{g}\) of \(\mathrm{SiO}_{2}\) are heated. If the actual yield of \(\mathrm{P}_{4}\) is 45.0 \(\mathrm{g}\) , determine the percent yield of \(\mathrm{P}_{4}\) .

Design a concept map for the following reaction. $$\mathrm{CaCO}_{3}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{CaCl}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(1)+\mathrm{CO}_{2}(\mathrm{g})$$ The concept map should explain how to determine the mass of \(\mathrm{CaCl}_{2}\) produced from a given mass of HCl.

Challenge When copper wire is placed into a silver nitrate solution \(\left(\mathrm{AgNO}_{3}\right)\), silver crystals and copper(II) nitrate \(\left(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\right)\) solution form. a. Write the balanced chemical equation for the reaction. b. If a 20.0-g sample of copper is used, determine the theoretical yield of silver. c. If 60.0 g of silver is recovered from the reaction, determine the percent yield of the reaction.

Categorize the ways in which a balanced chemical equation can be interpreted.

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