Chapter 10: Problem 40
Determine the number of moles present in each compound. a. 22.6 \(\mathrm{g} \mathrm{AgNO}_{3}\) b. 6.50 \(\mathrm{g} \mathrm{ZnSO}_{4}\) c. 35.0 \(\mathrm{g} \mathrm{HCl}\)
Short Answer
Expert verified
The number of moles present in each compound are as follows:
a. 0.133 mol of AgNO3
b. 0.040 mol of ZnSO4
c. 0.960 mol of HCl
Step by step solution
01
Determine the molar mass of AgNO3
To determine the molar mass of AgNO3, we need to add the molar masses of its constituent elements: silver (Ag), nitrogen (N), and oxygen (O).
Molar mass of AgNO3 = (Molar mass of Ag) + (Molar mass of N) + (3 * Molar mass of O)
Using the periodic table, we find the molar masses:
Ag = 107.87 g/mol
N = 14.01 g/mol
O = 16.00 g/mol
Molar mass of AgNO3 = 107.87 + 14.01 + (3 * 16.00) = 169.88 g/mol
02
Divide mass of AgNO3 by molar mass
Now, we'll divide the given mass of 22.6 g of AgNO3 by its molar mass of 169.88 g/mol:
Number of moles of AgNO3 = (22.6 g) / (169.88 g/mol)
03
Calculate the number of moles
Finally, we calculate the number of moles:
Number of moles of AgNO3 = 0.133 mol
b. 6.50 g ZnSO4
04
Determine the molar mass of ZnSO4
To determine the molar mass of ZnSO4, we need to add the molar masses of its constituent elements: zinc (Zn), sulfur (S), and oxygen (O).
Molar mass of ZnSO4 = (Molar mass of Zn) + (Molar mass of S) + (4 * Molar mass of O)
Using the periodic table, we find the molar masses:
Zn = 65.38 g/mol
S = 32.07 g/mol
O = 16.00 g/mol
Molar mass of ZnSO4 = 65.38 + 32.07 + (4 * 16.00) = 161.45 g/mol
05
Divide mass of ZnSO4 by molar mass
Now, we'll divide the given mass of 6.50 g of ZnSO4 by its molar mass of 161.45 g/mol:
Number of moles of ZnSO4 = (6.50 g) / (161.45 g/mol)
06
Calculate the number of moles
Finally, we calculate the number of moles:
Number of moles of ZnSO4 = 0.040 mol
c. 35.0 g HCl
07
Determine the molar mass of HCl
To determine the molar mass of HCl, we need to add the molar masses of its constituent elements: hydrogen (H) and chlorine (Cl).
Molar mass of HCl = (Molar mass of H) + (Molar mass of Cl)
Using the periodic table, we find the molar masses:
H = 1.01 g/mol
Cl = 35.45 g/mol
Molar mass of HCl = 1.01 + 35.45 = 36.46 g/mol
08
Divide mass of HCl by molar mass
Now, we'll divide the given mass of 35.0 g of HCl by its molar mass of 36.46 g/mol:
Number of moles of HCl = (35.0 g) / (36.46 g/mol)
09
Calculate the number of moles
Finally, we calculate the number of moles:
Number of moles of HCl = 0.960 mol
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass Calculation
Molar mass is the weight of a substance's elements combined to produce a given compound. When you calculate molar mass, you take the atomic masses of all the atoms present in the compound and add them together. This gives the mass of one mole of that compound in grams. The unit for molar mass is grams per mole (g/mol). For example, to find the molar mass of silver nitrate, AgNO3, you would:
- Find the mass of each element in the compound: silver (Ag) is 107.87 g/mol, nitrogen (N) is 14.01 g/mol, and oxygen (O) is 16.00 g/mol.
- Add these together, considering there are three oxygen atoms: 107.87 + 14.01 + (3 * 16.00) = 169.88 g/mol.
Chemical Formula Interpretation
Interpreting chemical formulas is essential for understanding what elements constitute a compound and how to determine their amounts. A chemical formula like ZnSO4 tells us directly:
- There is one atom of zinc (Zn).
- There is one atom of sulfur (S).
- There are four atoms of oxygen (O).
Periodic Table Usage
The periodic table is an essential tool in chemistry for obtaining information about various elements. Each element’s position tells us about its atomic number, group, period, and atomic mass, which is vital for calculating molar masses.
- Atomic Mass: Located beneath the element symbol, atomic mass is crucial for determining how much one mole of an element weighs. For example, hydrogen (H) has an atomic mass of 1.01 g/mol.
- Groups and Periods: Elements are organized into columns called groups and rows called periods, which help in predicting element properties and their chemical behavior.