Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Making Candy A recipe for pralines calls for the candy mixture to be heated until it reaches the "soft ball" stage, at about \(236^{\circ} \mathrm{F}\) . Can a Celsius thermometer with a range of \(-10\) to \(110^{\circ} \mathrm{C}\) be used to determine when the "softball" stage is reached? (Chapter 2)

Short Answer

Expert verified
The "soft ball" stage is reached at \(236^{\circ}\mathrm{F}\), which is approximately \(113.33^{\circ}\mathrm{C}\). Since the Celsius thermometer has a range of \(-10\) to \(110^{\circ}\mathrm{C}\), it cannot be used to determine when the "softball" stage is reached, as the required temperature exceeds its range.

Step by step solution

01

Understand the temperature conversion formula.

To convert a temperature from Fahrenheit to Celsius, we can use the following formula: \[C = \frac{5}{9}(F-32)\] where C is the temperature in Celsius, and F is the temperature in Fahrenheit.
02

Retrieve the given temperature in Fahrenheit.

We are given that the "soft ball" stage is reached at a temperature of \(236^{\circ}\mathrm{F}\).
03

Convert the temperature to Celsius.

Using the formula from step 1, we plug in the given Fahrenheit temperature to find the corresponding Celsius temperature: \[C = \frac{5}{9}(236-32)\] Now, let's calculate the value inside the parentheses: \[236 - 32 = 204\] So, the formula becomes: \[C = \frac{5}{9}(204)\]
04

Calculate the Celsius temperature.

Now, let's solve the equation for C: \[C = \frac{5}{9}(204) = \frac{1020}{9} = 113.33\] The Celsius temperature equivalent of the "soft ball" stage is approximately \(113.33^{\circ}\mathrm{C}\).
05

Check if the Celsius temperature is within the range of the thermometer.

We are given that the Celsius thermometer has a range of \(-10\) to \(110^{\circ}\mathrm{C}\). Since \(113.33^{\circ}\mathrm{C}\) is greater than the upper limit (\(110^{\circ}\mathrm{C}\)) of the given thermometer range, we can conclude that the Celsius thermometer cannot be used to determine when the "softball" stage is reached.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fahrenheit to Celsius
When engaging in activities like praline candy making, understanding temperature conversions is key, especially for recipes requiring precision. Often, temperatures in recipes are given in Fahrenheit, prompting the need for conversion to Celsius for equivalence. This is vital when you have access to a thermometer that measures only in Celsius. The standard formula used for this conversion is:\[ C = \frac{5}{9}(F - 32) \]where:
  • \(C\) represents the temperature in degrees Celsius
  • \(F\) represents the temperature in degrees Fahrenheit
This formula adjusts for the difference in starting points of the two scales (32 degrees being the freezing point in Fahrenheit) and the different scale increments (9 degrees in Fahrenheit equals 5 degrees in Celsius).
By substituting \(236^{\circ}F\) into this formula, you can reliably translate this to approximately \(113.33^{\circ}C\). This guides you accurately when comparing against the specified limits of your Celsius thermometer.
praline candy making
Praline candy making is an artful process that requires precise temperature control to achieve the desired texture and flavor. The mention of 'soft ball' stage in candy making is crucial. This term refers to a specific stage in sugar syrup cooking, where the boiling sugar solution forms a soft, malleable ball when dropped in cold water.
Achieving the correct temperature for this stage is essential since it directly influences the texture and firmness of the final praline product. For pralines, this 'soft ball' stage occurs when the mixture reaches around \(236^{\circ}F\) (or roughly \(113.33^{\circ}C\)).
  • Getting this temperature right ensures the pralines will not be too hard or too soft.
  • It guarantees the pralines develop the trademark creamy consistency.
Using an accurate thermometer helps maintain control over the cooking process, ensuring success in producing quality pralines.
Celsius thermometer range
For anyone working with kitchen thermometers, understanding their range is critical. A thermometer with a limited Celsius range can prove inadequate, especially when precise temperature control is needed for specific recipes, like praline candy making. The mentioned thermometer range of \(-10^{\circ}C\) to \(110^{\circ}C\) can miss out on marking crucial temperatures needed for some cooking processes.
With the 'soft ball' temperature for pralines at around \(113.33^{\circ}C\), this specific thermometer would exceed its maximum threshold. Important considerations include:
  • Understanding the maximum and minimum measurable temperatures of the thermometer.
  • Ensuring your cooking requirements fall within this range.
  • Considering an alternative or higher-range thermometer if readings surpass the available limits.
For precision in growth in culinary skills, knowing these constraints and planning for solutions enhances both confidence and success in recipes like praline candy.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

How many moles are present in 1.00 g of each compound? a. L-tryptophan \(\left(\mathrm{C}_{11} \mathrm{H}_{12} \mathrm{N}_{2} \mathrm{O}_{2}\right),\) an essential amino acid b. magnesium sulfate heptahydrate, also known as Epsom salts c. propane \(\left(\mathrm{C}_{5} \mathrm{H}_{8}\right),\) a fuel

If you could count two atoms every second, how long would it take you to count a mole of atoms? Assume that you counted continually for 24 hours every day. How does the time you calculated compare with the age of Earth, which is estimated to be \(4.5 \times 10^{9}\) years old?

Patina The Statue of Liberty has turned green because of the formation of a patina. Two copper compounds, \(\mathrm{Cu}_{3}(\mathrm{OH})_{4} \mathrm{SO}_{4}\) and \(\mathrm{Cu}_{4}(\mathrm{OH})_{6} \mathrm{SO}_{4},\) form this patina. Find the mass percentage of copper in each compound.

Two different compounds are composed of Elements \(\mathrm{X}\) and \(\mathrm{Y}\) . The formulas of the compounds are \(\mathrm{X}_{2} \mathrm{Y}_{3}\) and \(\mathrm{XY}\) . A 0.25 mol sample of \(\mathrm{XY}\) has a mass of \(17.96 \mathrm{g},\) and a 0.25 mol sample of \(\mathrm{X}_{2} \mathrm{Y}_{3}\) has a mass of 39.92 \(\mathrm{g}\) . a. What are the atomic masses of elements \(\mathrm{X}\) and \(\mathrm{Y}\) ? b. What are the formulas for the compounds?

How many moles contain the given quantity? a. \(1.25 \times 10^{15}\) molecules of carbon dioxide b. \(3.59 \times 10^{21}\) formula units of sodium nitrate c. \(2.89 \times 10^{27}\) formula units of calcium carbonate

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free